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qwelly [4]
3 years ago
6

A force of 265.1 N acts on an object to produce an acceleration of 14.52 m/s^2. What is the mass of the object?

Physics
2 answers:
astra-53 [7]3 years ago
6 0

The answer is :


18.26


Hope I helped.

Lady bird [3.3K]3 years ago
4 0

Answer:

The mass of the object is 18.26kg

Explanation:

We know by Newton's second law we know that a force applied on an object is equal to its mass times the acceleration caused by the force:

F=ma

From this equation, solving for the mass:

m=\frac{F}{a}

Plugging in the values:

m=\frac{265.1N}{14.52m/s^2}=18.26kg

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The conservation of energy principle applies to a. all systems. b. open systems. c. closed systems. d. Ideal gas systems.
Ainat [17]

Answer:closed systems

Explanation:

A closed system is one in which matter does not enter or leave the system but there is exchange of energy between the system and its environment. In a closed system, the principle of energy conservation applies. The principle of energy conservation states that energy can neither be created nor destroyed but is converted from one form to another. An example of a closed system is a reaction vessel whose lid is closed.

5 0
3 years ago
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2 Ten identical lengths of wire are laid closely side-by-
Mice21 [21]

Answer:

(a) 0.71 mm

(b) 0.158 cubic cm

Explanation:

The width of one wire is the diameter of the wire.

(a) Let the diameter of each wire is d.

So, 10 d = 14.2 mm

d = 1.42 mm

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(b) Length, L = 10 cm

The volume of the single wire is given by

V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3

7 0
2 years ago
Newtons laws of motion
Viktor [21]

Answer:

Law 1. A body continues in its state of rest, or in uniform motion in a straight line, unless acted upon by a force.

Law 2. A body acted upon by a force moves in such a manner that the time rate of change of momentum equals the force.

Law 3. If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction.

7 0
2 years ago
A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children
trasher [3.6K]

Answer:

The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

                     

Explanation:

The centripetal acceleration is given by:

a_{c} = \frac{v^{2}}{r}

Where:

v^{2}: is the tangential speed = 9.50 m/s

r: is the distance = 6.00 m

Hence, the centripetal acceleration is:

a_{c} = \frac{v^{2}}{r} = \frac{(9.50 m/s)^{2}}{6.00 m} = 15.04 m/s^{2}

Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

I hope it helps you!

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2 years ago
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