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frez [133]
3 years ago
7

Identify the molecule that is a carbohydrate.

Chemistry
2 answers:
rosijanka [135]3 years ago
3 0
The answer is lipid

i just answered the same question
natali 33 [55]3 years ago
3 0
The answer would be a lipid,lipids are fats and pretty much so are carbs so the answer would be. D
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kvasek [131]
A mirror reflects light
5 0
3 years ago
What is the identity of a gas that has a density of 1.4975 g/L and a volume of 8.64 L at a pressure of 2.384 atm and with a temp
bagirrra123 [75]
Answer: H2O (water)

Explanation:

The answer choices for this question are:

A) H2O
B) N2
C) SO2
D) NO3
E) Cl2

The solution of the problem is:

1) Data:

<span> density, d = 1.4975 g/liter
volume, V = 8.64 liter
pressure, p = 2.384 atm
temperature, T = 349.6 K

2) Formulas:

d = m/V => m = d*V

n = m / molar mass => molar mass = m / n

pV = nRT => n = pV / RT

3) Solution

n = pV / RT = 2.384 atm * 8.64 liter / (0.0821 atm*liter/K*mol * 349.6K)

n = 0.7176 moles

</span>m = dV = 1.4975 g/ liter * <span>8.64 liter = 12.9384 g

molar mass = m / n = 12.9384 g / 0.7176 moles = 18.03 g/mol

That molar mass corresponds to the molar mass of water, therefore the gas is H2O (water vapor).</span>
5 0
3 years ago
A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200
Anarel [89]

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

Volume of the box ,V= s^3

V=(20.0 cm)^3=8000 cm^3=8\times 10^{-3} m^3

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

\mu=\sqrt{\frac{3kN_AT}{M}}

where,

= root mean square speed

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature = 370 K

M = mass helium = 3.40\times 10^{-27}kg/mole

N_A = Avogadro’s number = 6.022\times 10^{23}mol^{-1}

T=\frac{\mu _{rms}^2\times M}{3kN_A}

Moles of helium gas = n

Number of helium molecules = N =2.00\times 10^{23}

N = N_A\times n

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

PV=\frac{N}{N_A}\times R\times \frac{\mu _{rms}^2\times M}{3kN_A}

PV=\frac{N\times R\times \mu ^2\times M}{3k\times (N_A)^2}

R=k\times N_A

PV=\frac{N\times \mu ^2\times M}{3}

P=\frac{2.00\times 10^{23}\times (200 m/s)^2\times 3.40\times 10^{-27} kg/mol}{3\times 8\times 10^{-3} m^3}

P=1133.33 Pa =1.133 kPa

(1 Pa = 0.001 kPa)

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

3 0
3 years ago
Please help mw with this
mart [117]

Answer:

I cannot see any picture

Explanation:

Please put a picture

7 0
3 years ago
Read 2 more answers
The percentage of Chlorine in the sample
seropon [69]
Im sorry really dont know the answer

4 0
3 years ago
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