The rate of a chemical reaction is NOT affected by which of the following:

What would the expected temperature change be (in Fahrenheit) ida 0.5 gran sample of water released 50.1 J of heat energy? The s

Mariana [72]

<h3>Answer:</h3>

23.95 °C

<h3>Explanation:</h3>

We are given;

Mass of the sample is 0.5 gram
Quantity of heat released as 50.1 Joules
Specific heat capacity is 4.184 J/g°C

We are required to calculate the change in temperature;

Quantity of heat absorbed is given by the formula;

Q = mass × specific heat capacity × Change in temperature

That is, Q = mcΔT

Rearranging the formula;

ΔT = Q ÷ mc

Therefore;

ΔT = 50.1 J ÷ (0.5 g × 4.184 J/g°C)

= 23.95 °C

Therefore, the expected change in temperature is 23.95 °C

4 0

4 years ago

While in Europe, if you drive 107km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter

Mumz [18]

That's a lot of conversions...
107*7 = 749km in one week
749/1.6 = 468.125 miles
468.125/39 = <span>12.0032051282 gallons of fuel needed
</span>1 gallon = 4.54609 litres
1.1(Cost per litre)*4.54609(Number of litres per gallon)*12.0032051282(Number of gallons needed) = <span>60.0244158814 euros cost per week
</span>60.0244158814 * 1.26 = <span>75.6307640105 dollar cost per week
</span>$75.63

7 0

3 years ago

Read 2 more answers

Plants and animals can build up or break down rock by increasing weathering, erosion, and

alexgriva [62]

Answer:

false

Explanation:

Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth. Water, ice, acids, salts, plants, animals, and changes in temperature are all agents of weathering.

6 0

3 years ago

Murphy built a simple motor with a battery, permanent magnet, copper coil of wire and iron bar. When the motor is turned on, the

aivan3 [116]

Answer:

Energy transformation between mechanical energy and electrical energy

Explanation:

Generally, when the copper coil and the iron bar rotate in a circular direction, there is change in the magnetic flux, and as a result an electromotive force (also known as EMF) is generated. The induced electromotive force is the voltage produced due to the presence of magnetic force due to the rotation of the coil and iron bar. Thus, the energy transformation between mechanical energy and electrical energy occurs.

3 0

3 years ago

Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4

Alinara [238K]

Answer : The balanced equations will be:

(a) $3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $2N_2O_5\rightarrow 2N_2+5O_2$

(c) $2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) $Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}$

The balanced equations will be:

$3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}$

The balanced equations will be:

$2N_2O_5\rightarrow 2N_2+5O_2$

(c) $Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}$

The balanced equations will be:

$2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

4 0

3 years ago