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3 years ago

Name these covalent compounds: SO2, P2CL5 and N2O4

Chemistry

1 answer:

Licemer1 [7]3 years ago

5 0

Answer:

SO2 => sulphur dioxide

P2CL5 =>Diphosphorus pentachloride

N2O4 =>Dinitrogen tetroxide

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A ball of mass 0.2 kg is dropped from a height of 10 m. How much mechanical energy does it have right before it hits the ground?

lana [24]

Answer:

19.6 J

Step-by-step explanation:

Before the ball is dropped, it has a potential energy

PE = mgh

PE = 0.2 × 10 × 9.8

PE = 19.6 J

Just before the ball hits the ground, the potential energy has been converted into kinetic (mechanical) energy.

KE = 19.6 J

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3 years ago

You place 10 grams of a salt into water and want it to dissolve. All of the following will cause a salt to dissolve faster excep

klio [65]

boiling, salt water will separate the salt from the water through the physical change of water from a liquid to a gas, leaving you with just salt left over.

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3 years ago

Determine the pH of 0.050 M HCN solution. HCN is a weak acid with a Ka equal to 4.9 x 10-10 DONE

nadezda [96]

Answer:

The pH of the solution is 5.31.

Explanation:

Let " $\alpha$ is the dissociation of weak acid - HCN.

The dissociation reaction of HCN is as follows.

$HCN+H_{2}O\rightarrow H_{3}O^{+}+CN^{-}$

Initial C 0 0

Equilibrium c(1- $\alpha$ ) c $\alpha$ c $\alpha$

Dissociation constant = $Ka= c\alpha \times \frac{c\alpha}{c(1-\alpha)}$

$=\frac{c\alpha^{2}}{(1-\alpha)}$

In this case weak acids $\alpha$ is very small so, (1- $\alpha$ ) is taken as 1.

$Ka=C\alpha^{2}$

$\alpha=\sqrt\frac{ka}{c}$

From the given the concentration = 0.050 M

Substitute the given value.

$\alpha=\sqrt\frac{4.9\times 10^{-10}}{0.05}=9.8\times 10^{-4}$

$[H_{3}O^{+}]=c\alpha$

$[H_{3}O^{+}]=0.05\times 9.8\times 10^{-4}= 4.9\times10^{-6}$

$pH= -log[H_{3}O^{+}]$

$=-log[4.9\times10^{-6}]$

$=6-log 4.9= 5.31$

Therefore, The pH of the solution is 5.31.

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3 years ago

Read 2 more answers

What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v

ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is $\lambda$ .

Formula to calculate thickness of a benzene thin film is as follows.

Optical path length through benzene ( $\lambda$ ) = $2 \times n \times d$

Hence, substituting the given values into the above formula as follows.

Optical path length through benzene = $2 \times n \times d$

d = $\frac{\text{Optical path length through benzene}}{2 \times n}$

= $\frac{\lambda}{2 \times n}$

= $\frac{615 \times 10^{-9}}{2 \times 1.501}$ (as 1 nm = $10^{-9}m$

= 204.9 m

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0

3 years ago

Can someone please help me with this?--20 pts!

katrin2010 [14]

Answer:

Compound B is ionic. The electronegativity difference is 2.2, which can be determined by subtracting the electronegativity of Element Y from that of Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.

Hope that helps.

3 0

3 years ago

Name these covalent compounds: SO2, P2CL5 and N2O4​

Name these covalent compounds: SO2, P2CL5 and N2O4