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3 years ago

Identify the Quedrant containing the point (3.27, -4.81)

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

Answer: Quadrant 4

Step-by-step explanation:

You might be interested in

Is 5.78778777... A rational or irrational number

Minchanka [31]

It is irrational because it does not repeat a pattern nor does it stop.

8 0

3 years ago

The graph shows the relationship between mass and volume for pure silver. Use the graph to determine the density of pure silver

Natalija [7]

Answer:

C. Slope and $10.49 g/cm^3$

Step-by-step explanation:

We're missing the graph itself, but I can make an educated guess:

- Assuming x = volume and y = mass:

$p = \frac{m}{v}$

density = mass/volume

x = volume = run

y = mass = rise

mass/volume = rise/run = slope

The slope of the line (assuming the graph is purely linear) represents mass/volume, which is the formula for density.

I had to Google the density of silver itself. Do the math from the graph for a more appropriate answer, as the graph may be less scientifically precise.

7 0

3 years ago

What is the midpoint

Tamiku [17]

Midpoint formula:

x, y = (x2+x1/2), (y2+y1/2)

x, y= (3+8/2), (4-4/2)

x, y= (5.5), (0)

Therefor the midpoint is (5.5, 0)

Hope I helped :)

7 0

3 years ago

The product of odd numbers is always even true or false ?

likoan [24]

Answer:

false

Step-by-step explanation:

let's say we have two odd numbers

2k+1 and 2t+1

$(2k+1)(2t+1)\\\\=4kt+2k+2t+1\\\\=2(2kt+k+t)+1$

so we see it's odd

6 0

3 years ago

Read 2 more answers

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

3 years ago