All categories

2 years ago

35.625 rounded to the nearest hundredth

Mathematics

1 answer:

Lelu [443]2 years ago

8 0

Answer:

35.63

Step-by-step explanation:

If you like to round 35.625 to the nearest hundredth, leaving only two numbers after the decimal point, then you have come to the right post.

You might be interested in

The ratio of teachers to students at Priory School is 2:27

Rzqust [24]

Answer:

609

Step-by-step explanation:

ratio of teachers to students at Priory School =2:27

Let X= total number of both the students and the teacher

Ratio of teacher=( 2/29)X

Ratio of student is (27/29 )X

But total number of teacher = 42

2/29 ×X =42

2X= 42×29

2X=1218

X= 609

Hence, school's total population is 609

4 0

2 years ago

One of the legs of a right triangle measured 6 cm and the other leg measures 17cm. Find the measure of the hypotenuse. If necess

uysha [10]

Answer:

don't no for the answer he app vapru naga he app bakwas ahe

5 0

2 years ago

Read 2 more answers

Simplify the expression 17y-2x+3(3x-y)+2x

Marat540 [252]

Answer:

9x+14y

Step-by-step explanation:

First Multiply the number outside of the brackets with the numbers inside the brackets. Ex:3 x 3x and 3 x -y

17y-2x+3(3x-y)+2x

That should get you to this.

17y-2x+9x-3y+2x

Next combine like terms.

14y+9x

Hope this helps!

5 0

3 years ago

C(x)=2x^2-400x+31,000

NemiM [27]

This is a quadratic so if you want to find the solutions, use the quadratic formula. Google quadratic formula and videos on it and how to use it will pop up.

7 0

3 years ago

You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the

il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that $n = 2809, \pi = \frac{1634}{2809} = 0.5817$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034$

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0

2 years ago