In ΔMNO, the measure of ∠O=90°, the measure of ∠M=46°, and NO = 96 feet. Find the length of OM to the nearest tenth of a foot.
1 answer:
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Answer: x = 31
Step-By-Step:
<u>To Find x:</u>
<u /> (Angle Sum Property Of Triangles)
(Remove the brackets)
<u /><u />
(Group Accordingly)
<u /><u />
=
=
=
=
=
=
<u>Therefore</u> x = 31
So,
Angle A = x + 10 = 31 + 10 = 41
Angle B = 2*x + 20 = 2*31 + 20 = 82
Angle C = 2*x - 5 = 62 - 5 = 57