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2 years ago

10

Please help guys -_-

2 answers:

baherus [9]2 years ago

5 0

Answer:

C. the remainder must always be less than the dividend

Kitty [74]2 years ago

3 0

Answer is C dividend

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Please help thank you!

kirill [66]

Question 1:

Look at the image.

First, we graph the points on a grid.

Then, we find the perpendicular bisectors and find where they intersect.

They intersect on the circumcenter of the triangle.

The circumcenter is (5,3)

Question 2:

The answer is III only because the perpendicular bisector for the longest side will always have to point outside the triangle in order to intersect with the other two perpendicular bisectors.

Question 3:

The answer is a perpendicular bisector because it is a perpendicular line that bisects a side of the triangles, which is the exact definition of a perpendicular bisector.

Have an awesome day! :)

3 0

2 years ago

2, 3, 5, 9, 17...

BARSIC [14]

Answer:

Step-by-step explanation:

i'm sure the answer is C

8 0

2 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

There are two humans , three dogs , two birds , five cats , and a spider in a room . How many legs are all together

bulgar [2K]

Answer:

all together there will be 44 legs

3 0

2 years ago

Solve for X <br> PLEASE HELP ITS URGENT

almond37 [142]

With pythagorean theorem and working backwards, you do 8100-1225 to get 6875, you then get the square root of that to get x=82.91 or rounded to 82.92

6 0

2 years ago

Read 2 more answers