1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MaRussiya [10]
3 years ago
11

The following data shows the quarterly profit (in thousands of dollars) made by a particular company in the past 3 years.

Mathematics
1 answer:
laiz [17]3 years ago
8 0

Answer:

208.82 ; 61.33

Step-by-step explanation:

Given the data:

Year Quarter Profit ($1000s)

1 1 45

1 2 51

1 3 72

1 4 50

2 1 49

2 2 45

2 3 79

2 4 54

3 1 42

3 2 58

3 3 70

3 4 56

The 3 period moving average :

Yr Qtr Profit ($1000s)Pt ____ Ft ____ e=(PT-Ft)²

1 _ 1 ___45 __

1 _ 2 __ 51 __

1 _ 3 __ 72 __

1 _ 4 __ 50 ______________56 ____ 36

2 _ 1 __ 49 ______________57.67__ 75.17

2 _ 2__ 45 ______________57 ____ 144

2 _ 3__ 79 ______________48 ____961

2 _ 4__ 54 ______________57.67 _ 13.47

3 _ 1__ 42 ______________59.33__300.33

3 _2 __ 58 ______________58.33__ 0.11

3 _ 3__ 70 ______________51.33__ 348.57

3 _ 4 __56 ______________56.67__0.45

MSE = Σ(Pt - Ft)² ÷ n

MSE = (36+75.17+144+961+13.47+300.33+0.11+348.57+0.75) ÷ 9

= 208.82

Forecast for next quarter :

(58 + 70 + 56) / 3 = 184 /3 = 61.33

You might be interested in
Help 20 points btw............
Nadya [2.5K]
You would do base times height
3 0
3 years ago
Please help me with 2b ASAP. <br> Really appreciate it!!
Bogdan [553]

f(x)=\dfrac{x^2}{x^2+k^2}

By definition of the derivative,

f'(x)=\displaystyle\lim_{h\to0}\frac{\frac{(x+h)^2}{(x+h)^2+k^2}-\frac{x^2}{x^2+k^2}}h

f'(x)=\displaystyle\lim_{h\to0}\frac{(x+h)^2(x^2+k^2)-x^2((x+h)^2+k^2)}{h(x^2+k^2)((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{(x+h)^2-x^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2xh+h^2}{h((x+h)^2+k^2)}

f'(x)=\dfrac{k^2}{x^2+k^2}\displaystyle\lim_{h\to0}\frac{2x+h}{(x+h)^2+k^2}

f'(x)=\dfrac{2xk^2}{(x^2+k^2)^2}

\dfrac{k^2}{(x^2+k^2)^2} is positive for all values of x and k. As pointed out, x\ge0, so f'(x)\ge0 for all x\ge0. This means the proportion of occupied binding sites is an increasing function of the concentration of oxygen, meaning the presence of more oxygen is consistent with greater availability of binding sites. (The question says as much in the second sentence.)

7 0
3 years ago
A state offers specialty license plates that contain 3 letters followed by 2 numbers. License plates are assigned randomly. All
Maslowich

Answer:

Step-by-step explanation:

# of ways to succeed: 10*10*10*3*25*25--# of possible plates: 10*10*10*26*26*26----P(exactly one W) = [10^3*3*25^2]/[10^3*26^3] = 3*25^2/26^2 = 1875/17576

4 0
2 years ago
Solve the system by substitution: -4.5x-2y=-12.15 3.25x-y=-0.75
valina [46]

Answer:

The answer is x=0.97 while y=3.90

4 0
3 years ago
A contractor estimates $2,400 to build a deck to a customer’s specifications, How much would it cost to build five similar decks
Bumek [7]
5*2400=$12,000 is the total costs for 5 decks costing $2,400 each.
3 0
3 years ago
Other questions:
  • the perimeter of a triangle is 17 cm. the second side is twice the length of the first side and the third side is 1cm less than
    13·1 answer
  • Which number line represents all the values of x for the question x (2) = 49
    8·1 answer
  • Review - Algebra 2 Test I (UP)
    6·1 answer
  • The perfect squares between 50 and 104
    8·2 answers
  • What is 24 cups equal to in gallons
    5·2 answers
  • Your class is learning to tie knots. Each student needs a piece of rope that is
    7·1 answer
  • What is the range of the function graphed above? A. B. C. D.
    8·1 answer
  • Describe the steps required to determine the equation of a quadratic function given its zeros and a point.
    9·1 answer
  • HELP PLEASE !!!!!!!!!
    14·2 answers
  • Need help on these questions
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!