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Mila [183]
3 years ago
9

Pls help I will give brainliest

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

At 1 hour the ship traveled 25 miles.

At constant speed, this means every 1 hour the ship travels 25 miles.

The speed would be 25 miles per hour.

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Where does each go (A,B,C,D,E,F,G,H,I,J)?
disa [49]

Answer:

for polynomial 4x^2-2x+14, degree=2/ special name=trinomial

for 22(x^2)(y^2)-2x+14, degree=2/ special name= trinomial

for 7x+2, degree=2/ binomial

for 2(x^3)-6xy+13xy^2, degree=3/ trinomial

for a^3-8, degree=3/ binomial

8 0
2 years ago
PLEASEE HELPPP MEE!!<br> what is the measure of angle 2?
Sergio039 [100]

Answer:61 degrees.

Step-by-step explanation: If you look at Line MN you will see 103 degrees on the left side. A line is 180 degrees so 180-103=77. Angle P is corresponding with the angle above. Becuase you want to find 2, you have to subtract 77 by 16 to get 61 degrees

3 0
3 years ago
The height of a flare fired from a 32-foot high platform can be modeled by the function h= -16t^2 + 16t + 32, where h is the hei
Amanda [17]

Answer:

Time, t = 2 seconds

Step-by-step explanation:

The height of a flare fired from a 32-foot high platform can be modeled by the function :

h= -16t^2 + 16t + 32

Here, h is the height in feet above the ground and t is the time in seconds.

It is required to find the time taken by the flare to reach the ground. When its reaches ground, height covered by it equals 0 such that,

h = 0

-16t^2 + 16t + 32=0\\\\t=\dfrac{-16+\sqrt{16^2-4\times (-16)(32)} }{2(-16)}, \dfrac{-16-\sqrt{16^2-4\times (-16)(32)} }{2(-16)}\\\\t=-1\ s, 2\ s

Neglecting t = -1 seconds, the time taken by the flare to reach the ground is 2 seconds.

4 0
3 years ago
How to solve<br><br> 3sin^2x= cos^2x
DochEvi [55]

I'll try it.
I just went through this twice on scratch paper.  The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous.  But I think I got it.

You said                                                 <span><u>3sin²(x) = cos²(x)</u>

Use this trig identity:  sin²(x) = 1 - cos²(x)   

                                   Plug it into the original equation for (x).

                                                     3(1 - cos²(x) )  =  cos²(x)

Remove parentheses on the left:    3 - 3cos²(x)  =  cos²(x)

Add  3cos²(x)  to each side:            3                  =  4cos²(x)

Divide each side by  4 :                  3/4  =  cos²(x)

Take the square root of each side:    <em>cos(x) = (√3) / 2</em> .

There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that

                           cos( <em><u>30°</u></em> )  =  </span><span><span>(√3) / 2 </span>.


</span>
7 0
3 years ago
I need help ASAP!!
Dmitrij [34]
Suggestion:

The width is the x value and the hight is the y value.

Plot the points on the graph as decimal if that helps.

The point at the bottom left is the origin (0,0)

I hope this helps.
5 0
2 years ago
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