Question

A random sample of 38 wheel chair users were asked whether they preferred cushion type A or B, and 28 of them preferred type A whereas only 10 of them preferred type B. Use a hypothesis test to assess whether it is fair to conclude that cushion type A is at least twice as popular as cushion type B.

Answer 1

Answer:

The statement that cushion A is twice as popular as cushion B cannot be verified

Step-by-step explanation:

From the question we are told that:

Sample size n=38

Type a size A $X_a=28$

Type a size B $X_b=10$  

Generally the probability of choosing cushion A P(a) is mathematically given by

$P(a)=\frac{28}{38}$

$P(a)=0.73$

Generally the equation for A to be twice as popular as B is mathematically given by

$P(b)+2P(b)=3P$

Therefore Hypothesis

$Null H_0: p \leq \frac{2P}{3P} \\Altenative H_A:p>\frac{2P}{3P}$

Generally the equation normal approx of p value is mathematically given by

$z=\frac{x-np_0-0.5}{\sqrt{np_0(1-p_0)} }$

$z=\frac{28-(38*2/3)_0-0.5}{\sqrt{38*2/3*1/3} }$

$z=0.75$

Therefore from distribution table

$Pvalue=1-\theta (0.75)$

$Pvalue=0.227$

Therefore there is no sufficient evidence to disagree with  the Null hypothesis $H_0$

Therefore the statement that cushion A is twice as popular as cushion B cannot be verified