Answer:
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.
Step-by-step explanation:
We have to make a hypothesis test to prove the claim that the average vertical jump of students differs from 15 inches.
The null and alternative hypothesis are:
The significance level is 0.10.
The sample mean is 17 and the sample standard deviation is 5.37.
The degrees of freedom are df=(20-1)=19.
The t-statistic is:
The two-sided P-value for t=1.67 is P=0.11132.
This P-value is bigger than the significance level, so the effect is not significant. The null hypothesis can not be rejected.
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.
Answer:
Simplified :
x = 13/12
(Mixed number) :
x = 1 1/12
Step-by-step explanation:
Answer:
6) x=9.75
10) Triangle OMN ~ Triangle ODK; SSS ~
11) SSS ~ theorem
12) SSS ~ theorem
Step-by-step explanation:
For #6, since the polygons are similar, then it must mean AD is congruent to JM and CD is congruent to LM. Now we can set up the proportion 39/20=x/5 and solve. Solving for x gets us x=9.75, so C is the correct choice
For #10, there's no information about angles whatsoever in the diagram, so B and C must be wrong. D must be wrong as well because if the triangles weren't similar, then why is OJ ~ JM and OK ~ KN? So thus, the triangles are similar by SSS.
For #11, this is sort of a no-brainer because there's no mention of angles, so D must be correct.
For #12, same concept, no mention of angles, all sides are similar to their respective sides of the different triangles, so A is correct.
Answer: X= 6-4^z/2
Step-by-step explanation: first you need to get rid of the 4. You subtract it from both sides. So now
2x=6-4 to the power of z
So now you need to get rid of the 2. You divide both sides by two. Then you get
X= 6-4^z/2
Answer:
16.5
Step-by-step explanation:
Given data to us is ,
- 20, 15, 14, 16, 17, 12, 20, 22 .
Arrange it in ascending order .
= 12 , 14 , 15 , 16 , 17 , 20 , 20 , 22
The middle most observation will be median in case n is odd and average of middlemost observations if n is even , that is n = 8 .
=> Middlemost observations = 16 , 17
=> Mean = 16 + 17 /2 = 33/2 = 16.5
