Since there are 1000 millilitres in 1 Liter. If we divide 25,000 by 1000 we get an answer of 25 Litres.
Answer:
2
Step-by-step explanatio: look at the chart
Answer:
The correct answer is A

Step-by-step explanation:
We want to determine the decimal equivalence of
.
We perform the long division as shown in the attachment.
Note that in carry out the long division, the denominator which is 3, will be outside the long division sign, while the numerator which is
, will be inside the long division sign.
We see that the quotient of our long division is
.
We can rewrite this as 
Therefore
.
Answer:

Step-by-step explanation:
The Universal Set, n(U)=2092


Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted
from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects, 
We need to work out first the scale factor of the side length
Side MN correspond to the side JK
Side MN = 3.5 cm
Side JK = 14 cm
Scale factor = 14/3.5 = 4
Side OM correspond to side LJ
Side OM = 12 cm
Side LJ = 12 × 4 = 48 cm