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Dvinal [7]
3 years ago
7

Can someone please please help with these questions?

Mathematics
1 answer:
wolverine [178]3 years ago
5 0
The answer to number seven is EDF!
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19. Stacy and Justin each created a number pattern. Stacy's rule is "Add 2." Justin's rule is "Add 4." Both the patterns start a
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Answer:

the answer is C

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Need help will mark Brainliest
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Answer:

confusion?

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your welcome

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Determine the x- and y- intercepts for the graph defined by the given equation.
Natalka [10]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤

x - intercept = ( \:  - 9 \: , \: 0 \: )

No \:  \:  \: y - intercept

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3 years ago
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Please help me solve this!!!!1 ASAP
Nimfa-mama [501]

Answer:

g(x) = - sqrt(x+8) reflected about the x axis and shifted 8 units to the left

h(x) = 2 sqrt(x) +1 is stretched by 2 in the y direction and shifted up 1 in the y direction

Step-by-step explanation:

y = f(x + C)  C > 0 moves it left

So we moved it 8 units to the left

y = −f(x)  Reflects it about x-axis

g(x) = - sqrt(x+8) reflected about the x axis and shifted 8 units to the left

y = f(x) + C  C > 0 moves it up

so we moved it up 1 units

y = Cf(x)  C > 1 stretches it in the y-direction

and stretched it by 2 in the y direction

h(x) = 2 sqrt(x) +1 is stretched by 2 in the y direction and shifted up 1 in the y direction

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3 years ago
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Sec^6x(secxtanx)-sec^4(secxtanx)=sec^5xtan^3x<br> Verify the trigonometric identity
mario62 [17]

I guess you mean

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan^3x

On the left side, we have a common factor of \sec^4x(\sec x\tan x)=\sec^5x\tan x, so that

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan x(\sec^2x-1)

Recall that

\sec^2x=1+\tan^2x

from which it follows that

\sec^5x\tan x(\sec^2x-1)=\sec^5x\tan x\tan^2x=\sec^5x\tan^3x

7 0
3 years ago
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