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Dvinal [7]
3 years ago
7

Can someone please please help with these questions?

Mathematics
1 answer:
wolverine [178]3 years ago
5 0
The answer to number seven is EDF!
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Gary earns $42,990 per year he is paid weekly he currently has a $456 per month car loan payment and he pays $1277 per year for
Ber [7]

Answer:

Yes

Step-by-step explanation:

There are about 52 weeks in a year, 42,990 ÷ 52 = 826.73076 ,

1277 ÷ 12 = 106.41666

826.73076 - 106.41666 = 720.3141

720.3141 - 456 = 264.3141

8 0
3 years ago
PQ has endpoints P(-4, -2) and Q(-6, 8). What is the length of segment PQ in simplest radical form?
harina [27]

Answer:

The answer is

<h2>2 \sqrt{26}  \:  \:  \:  \: units</h2>

Step-by-step explanation:

The distance between two points of a line segment can be found by using the formula

d =  \sqrt{ ({x_1 - x_2})^{2} +  ({y_1 - y_2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(-4, -2) and Q(-6, 8)

The length of the line segment is

|PQ|  =  \sqrt{ ({ - 4 + 6})^{2} +  ({ - 2 - 8})^{2}  }  \\  =  \sqrt{ {2}^{2}  +  ({ - 10})^{2} }  \\  =  \sqrt{4 + 100}  \\  =  \sqrt{104}  \:  \:  \:  \:  \:  \:  \:  \\  = 2 \sqrt{26}  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

2 \sqrt{26}  \:  \:  \:  \: units

Hope this helps you

6 0
3 years ago
Find the line integral with respect to arc length ∫C(9x+5y)ds, where C is the line segment in the xy-plane with endpoints P=(2,0
Gemiola [76]

(a) You can parameterize <em>C</em> by the vector function

<em>r</em><em>(t)</em> = (<em>x(t)</em>, <em>y(t)</em> ) = <em>P</em> (1 - <em>t </em>) + <em>Q</em> <em>t</em> = (2 - 2<em>t</em>, 7<em>t</em> )

where 0 ≤ <em>t</em> ≤ 1.

(b) From the above parameterization, we have

<em>r</em><em>'(t)</em> = (-2, 7)   ==>   ||<em>r</em><em>'(t)</em>|| = √((-2)² + 7²) = √53

Then

d<em>s</em> = √53 d<em>t</em>

and the line integral is

\displaystyle\int_C(9x(t)+5y(t))\,\mathrm ds = \boxed{\sqrt{53}\int_0^1(17t+18)\,\mathrm dt}

(c) The remaining integral is pretty simple,

\displaystyle\sqrt{53}\int_0^1(17t+18)\,\mathrm dt = \sqrt{53}\left(\frac{17}2t^2+18t\right)\bigg|_{t=0}^{t=1} = \boxed{\frac{53^{3/2}}2}

6 0
3 years ago
A trapezoid is made of a square with side lengths of 7 feet and an isosceles right triangle whose base and height are both 7 fee
SVETLANKA909090 [29]
Check the picture below.

7 0
3 years ago
In a jury trial, suppose the probability the defendant is convicted, given guilt, is 0.95, and the probability the defendant is
Artyom0805 [142]

Answer:

The probability of the defendant is innocent given the defendant is convicted is P=0.006.

Step-by-step explanation:

Being:

G: guilty, I:innocent, C: convicted, A: acquitted.

We need to calculate P(I|C).

Being innocent, given convicted, is equal to the probability of being innocent and convicted divided by the probability of being convicted (innocent or guilty)

P(I|C)=\frac{P(I\&C)}{P(C)}

The probability of being innocent and convicted is

P(I\&C)=P(C|I)*P(I)=0.05*0.1=0.005

The probability of being convicted is equal to the sum of P(I&C) and P(G&C)

P(C)=P(I\&C)+P(I\&C)=P(C|I)*P(I)+P(C|G)*P(G)\\\\P(C)=0.005+0.95*0.90=0.005+0.855=0.86

Then,

P(I|C)=\frac{P(I\&C)}{P(C)}=\frac{0.005}{0.86}= 0.006

6 0
3 years ago
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