All categories

2 years ago

Factor this trinomial: 5x^2-12x+4 Please show all work I'll give Brainliest

Mathematics

2 answers:

Usimov [2.4K]2 years ago

8 0

Answer:

(x - 2)(5x - 2)

Step-by-step explanation:

5x² - 12x + 4

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 5 × 4 = 20 and sum = - 12

the factors are - 10 and - 2

use these factors to split the x- term

5x² - 10x - 2x + 4 ( factor the first/second and third/fourth terms )

= 5x(x - 2) - 2(x - 2) ← factor out (x - 2) from each term

= (x - 2)(5x - 2) ← in factored form

Vinvika [58]2 years ago

7 0

Answer:

x = 2

x = 2/5

Step-by-step explanation:

multiply 5 and 4

5* 4 = 20

what 2 numbers added make -12 and multiplied make 20 at the same time?

-10 and -2 do this

5 ( x - 10/5) (x - 2/5) = 0

simplify

5 ( x - 2) ( x - 2/5) = 0

(5( x - 2) ( x - 2/5))/5 = 0/5

( x - 2) ( x - 2/5) = 0

x = 2 x = 2/5

You might be interested in

What is the slope of the line through (1, -1) and (5. – 7)?

Vladimir [108]

Answer:

-3/2

Step-by-step explanation:

Given two points, we can find the slope by

m = (y2-y1)/(x2-x1)

= (-7 - -1)/ (5-1)

= (-7+1)/(5-1)

= -6/4

= -3/2

6 0

3 years ago

Read 2 more answers

If a*b means ab², what is the value of 5*4

suter [353]

Answer:

hhuh eud e uue dui7d iiit

8 0

2 years ago

Read 2 more answers

Binomial Probability

ASHA 777 [7]

Answer:

4.39% theoretical probability of this happening

Step-by-step explanation:

For each coin, there are only two possible outcomes. Either it lands on heads, or it lands on tails. The probability of a coin landing on heads is independent of other coins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Theoretically, a fair coin

Equally as likely to land on heads or tails, so $p = \frac{1}{2} = 0.5$

10 coins:

This means that $n = 10$

What is the theoretical probability of this happening?

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{10,2}.(0.5)^{2}.(0.5)^{8} = 0.0439$

4.39% theoretical probability of this happening

6 0

3 years ago

A pet store has 2 gray rabbits one eight of the rabbits at the pet store are gray. How many rabbits does the pet store have?

Eduardwww [97]

2 = 1/8
2 x 8 = 16
16 = 8/8
Glad to Help!

3 0

3 years ago

7-7(5+x)-9x in simplified

Luden [163]

Answer:

-28 - 16x

Step-by-step explanation:

7-7(5+x)-9x

Distribute

7 - 35 -7x -9x

Combine like terms

-28 - 16x

5 0

3 years ago