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user100 [1]
3 years ago
5

Given that

Mathematics
2 answers:
Alexus [3.1K]3 years ago
5 0
A) Substitute -6 for where x is in the expression...
g(-6) = 3(-6)^2 + 2(-6) + 5
g(-6) = 3(36) + 2(-6) + 5
g(-6) = 108 + 2(-6) + 5
g(-6) = 108 - 12 + 5
g(-6) = 96 + 5
g(-6) = 101

b) Substitute (p + 2) into where x is...
g(p + 2) = 3(p + 2)^2 + 2(p + 2) + 5
g(p + 2) = 3(p + 2)(p + 2) + 2(p + 2) + 5
g(p + 2) = 3(p^2 + 4p + 4) + 2(p + 2) + 5
g(p + 2) = 3p^2 + 12p + 12 + 2(p + 2) + 5
g(p + 2) = 3p^2 + 12p + 12 + 2p + 4 + 5
g(p + 2) = 3p^2 + 14p + 21

Lelu [443]3 years ago
5 0
A.
sub -6 for x

g(-6)=3(-6)^2+2(-6)+5
g(-6)=3(36)-12+5
g(-6)=108-7
g(-6)=101



b.
sub p+2 for x
g(p+2)=3(p+2)^2+2(p+2)+5
g(p+2)=3(p^2+4p+4)+2p+4+5
g(p+2)=3p^2+12p+12+2p+9
g(p+2)=3p^2+14p+21
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Joshua has a bag of marbles. In the bag are 5 white marbles, 3 blue marbles, and 7 green marbles. Peter randomly draws one marbl
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Answer:

1 / 5

Step-by-step explanation:

Given that:

Number of white marbles = 5

Number of blue marbles = 3

Number of green marbles = 7

Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :

Probability = required outcome / Total possible outcomes

Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles

First draw:

P(Green) = 7 / 15

Second draw:

Required outcome = 7 - 1 = 6

Possible outcomes = 15 - 1 = 14

P(green) = 6 / 14

Probability of drawing out two green marbles :

(7/15 * 6/14) = 42 / 210 = 1 / 5

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3 years ago
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dybincka [34]

Answer: 2f

Explanation:

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2 years ago
I need help with math, I have no idea what I'm doing
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