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lina2011 [118]
3 years ago
7

Help test due tonight! *no links please *

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

it Will be(-9,-6)

Step-by-step explanation:

reflecting (9,6) over the x axis gives the point (9,6) (The y coordinate changes sign)Reflecting this over the y axis will give the point (-9,-6) Answer

"good luck dude"

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Sum and difference of 5+2.3
professor190 [17]

Answer:

sum: 7.3 difference:2.7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help pls! if f(x) =6x-4, evaluate f(x)/-4 for x=8
irga5000 [103]
So first of all you need to plug in the x=8 into both equations which will make  the first equation be equals to 44 than plug in the x into the second equation and you will get 4 over -1 so in my opinion it should be b=44
5 0
3 years ago
2r2 + 3s3 − r2 + 4t2 − r2 if r = −2, s = −3, and t = 5.
Elza [17]

First, simplify the expression 2r^2 + 3s^3 - r^2 + 4t^2 - r^2. Here you have three terms with r^2, group them in the following way:

2r^2 + 3s^3 - r^2 + 4t^2 - r^2=2r^2-r^2-r^2+3s^3+4t^2=(2r^2-r^2-r^2)+3s^3+4t^2=

=r^2(2-1-1)+3s^3+4t^2=3s^3+4t^2.

Then substitute s=-3 and t=5:

3s^3+4t^2=3\cdot (-3)^3+4\cdot 5^2=3\cdot (-27)+4\cdot 25=-81+100=19.

Answer: 19.

3 0
3 years ago
Read 2 more answers
Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)
dimaraw [331]

Answer:

1. Option D. 15x²

2. Option C. 3

Step-by-step explanation:

1. Determination of the area of one section.

Length (L) of one section = 25x/5 = 5x

Width (W) of one section = 3x

Area (A) of one section =?

The area of one section can be obtained as follow:

Area (A) = Length (L) × Width (W)

A = L × W

A = 5x * 3x

A = 15x²

Thus, the area of one section is 15x²

2. Determination of the expressions that are equivalent to (p²)³.

We'll begin by simplifying (p²)³. This can be obtained as follow:

(p²)³ = p²*³

(p²)³ = p⁶

Next we shall compare each expression given in the question above to see which will be the same as p⁶.

p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹

p × p × p × p × p × p = p⁶

p² × p² × p² = p²⁺²⁺²

p² × p² × p² = p⁶

p² × p³ = p²⁺³

p² × p³ = p⁵

Thus,

p² × p³ ≠ p⁶

p⁵ ≠ p⁶

p⁶ = p⁶

SUMMARY

p × p × p × p × p × p = p⁶ = (p²)³

p² × p² × p² = p⁶ = (p²)³

p⁶ = (p²)³

Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.

6 0
3 years ago
4. What is the least common denominator of: *<br><br> 7<br> 12<br> and<br> 5<br> 6
Kaylis [27]

Answer:

Step-by-step explanation:

LCM of 7/12 and 5/6

12: 12, 24

6: 6, 12

LCM: 12

8 0
3 years ago
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