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alexgriva [62]
3 years ago
10

Am I right about this or..?

Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

Correct, as 4 is the only number repeating twice

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If 1 cm represents 35 miles what is 1.25 cm in miles?
lapo4ka [179]

Answer:

43.75 miles

Step-by-step explanation:

You divide the 35 by 4 and then just add it to the original distance of 35 miles. 35/4=8.75

8.75+35=43.75

8 0
3 years ago
Help on this please.
Komok [63]

Answer:

80 or 81

Step-by-step explanation:

6 0
2 years ago
Find the missing dimension. Use the scale 1:5
MrRissso [65]

Answer: 1m

Step-by-step explanation:

since model is 20cm, a 1:5 scale means the actual is 5x as big. since 20cm x 5 is 100 cm and 1m is 100 cm, the answer in the box should be 1.

4 0
2 years ago
In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per
Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, P_0=450,000

Growth rate is, r=5\%=0.05

Final population is, P=700,000

A population growth is an exponential growth and is modeled by the following function:

P=P_0(1+r)^x

Taking log on both sides, we get:

\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}

Plug in all the given values and solve for 'x'.

x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10

So, for x > 9.13, the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0
3 years ago
If f(x) varies directly with x and f(x) = 48 when x = 8 find the value of f(x) when x = 2
const2013 [10]
Here, f(x) = kx

k = f(x)/x
k = 48/8
k = 6

So, when x = 2, 
f(x) = 6 * 2
z = 12

In short, Your Answer would be: 12

Hope this helps!
6 0
3 years ago
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