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GaryK [48]
3 years ago
7

Al trazar en el plano cartesiano el angulo a cuyo lado terminal es el punto de ( 3,4). Los valores de las funciones del coseno y

cocecante son
Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

cos(\alpha)=\frac{3}{5}=0.6

cosec(\alpha)=\frac{5}{4}=1.25

Step-by-step explanation:

El cos(α) se define como el cociente entre el cateto adyacente y la hipotenusa.

El valor del cateto adyacente en nuestgro caso es CA = 3.

La hipotenusa se calcual de la siguiente manera:

h=\sqrt{3^2+4^2}=5

Por lo tanto, el cos(α) sera:

cos(\alpha)=\frac{3}{5}=0.6

El cosec(α)=h/CO.

El cateto opuesto CO = 4 y la hipotenusa h = 5

Por lo tanto, el cosec(α) sera:

cosec(\alpha)=\frac{5}{4}=1.25

Espero te haya sido de ayuda!

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Problem B
Lyrx [107]

Answer:

The years are:

  • 1000 BCE, 999 BCE, 888 BCE, 777 BCE, 666 BCE, 555BCE, 444 BCE. 333 BCE, 222 BCE, 111 BCE
  • 111 CE, 222 CE, 333 CE, 444 CE, 555 CE, 666 CE, 777 CE, 888 CE, 999 CE, 1000CE, 1011 CE, 1101 CE, 1110 CE,1222CE, 1333CE, 1444CE, 1555 CE, 1666 CE, 1777CE, 1888 CE, 1999CE, and 2000 CE

Explanation:

<u>1. Years BC:</u>

a) Years with four digits:

The first number with 3 equal digits is 1000. After that the years go decreasing: 999, 998, 997, ...

b) Years with three digits:

From 999 to 111, the numbers have three digits, thus the only that are solutions ara 999, 888, 777, 666, 555, 444, 333, 222, and 111: 9 numbers

After that the years have two digits, thus no solutions, with two digits.

Hence, we count 10 different years.

<u>2. Years CE</u>

a) Years with three digits:

  • 111, 222, 333, 444, 555, 666, 777, 888, 999: 9 years

b) Years with four digits

i) Starting with 1:

  • With three 0: 1000: 1 year
  • With three 1: 1011, 1101, 1110: 3 years
  • With three digits different to 1: 1222, 1333, 1444, 1555, 1666, 1777, 1888, 1999: 8 years

ii) Starting with 2:

  • With three 0: 2000: 1 year

The next one with three equal digits is 2111 and it is after 2020 CE.

Therefore, 9 + 1 + 3 + 8 + 1 = 22 years starting with 2.

<u>3. Total</u>

<u />

10 years BC and 22 years CE have exactly three digits the same: 10 + 22 = 32.

3 0
4 years ago
An auditorium has 30 rows of seats. The first row has 20 seats, the second row has 22 seats, the third row has 24 seats, and so
gayaneshka [121]
An = a1 + (n-1)*d
n = term to find = 30
a1 = first term = 20
d = common difference = 2

a30 = 20 + (30 - 1) * 2
a30 = 20 + 29 * 2
a30 = 20 + 58
a30 = 78

sn = (n (a1 + a30)) / 2
s30 = (30(20 + 78) / 2
s30 = (30(98) / 2
s30 = 2940/2
s30 = 1470 <===

6 0
3 years ago
Read 2 more answers
Help me with this please!
ruslelena [56]
Area of the quarter sector 
Area of the entire circle = pi * r^2
Area of the quarter circle = pi r^2 / 4
r = 9
Area of the quarter circle = pi 9^2 / 4
Area of the quarter circle = pi 81/4 = 20.25 pi

Area of the triangle
Area pf the triangle = 1/2 b*h
b = h = r
r = 9
Area of the triangle = 1/2 9 * 9 
Area of teh triangle = 1/2 81
Area of the triangle = 40.5

Area of the shaded area
The shaded area = Area of the 1/4 circle - area of the triangle
The shaded area = (20.24 pi - 40.5)ft^2

 A <<<<<< Answer.
6 0
3 years ago
HELPPPPPP PLEASE !! I appreciate it
Mila [183]
Helppppppp PLEASE !! I appreciate it

The awnser would be 30.


Heart & comment
4 0
3 years ago
Japhus Moore's credit card statement showed a previous balance of $921.07 , a financial charge of $13.80, new purchases of $962.
lara [203]

Answer:

$906.51

Step-by-step explanation:

5 0
4 years ago
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