(-4,-5)(-6,3)
slope(m) = (3 - (-5) / (-6 - (-4)
slope(m) = (3 + 5) / (-6 + 4)
slope(m) = 8/-2 = -4
y = mx + b
slope(m) = -4
u can use either of ur points...I will use (-6,3)
3 = -4(-6) + b
3 = 24 + b
3 - 24 = b
- 21 = b <== here ya go
What is the domain and the range of the relation represented by the ordered pairs? {(6,6),(−1,3),(3,6),(0,4)}{(6,6),(−1,3),(3,6)
Inessa [10]
Hello,
Let's review: The domain is all the possible x values of a relation/function. To get the domain, we look at the x values in the ordered pairs.
The domains are: {-1, 0, 3, 6} - as you can see these are the x values of each pair.
Let's review: The range is all the possible y values in a relation/function. To find the rang, we look at the y values of the pairs.
The ranges are: {3, 4, 6} - notice how there are two "6" in those pairs, and when writing the range, you don't need to repeat the number if it's already written.
I hope this helps! =)
May
The value of sector KL is 52
If JM and KN are two diamters of the circle,
then they intersect at the center
The sector JK and NM are equal
Thus,
The sector JN and KM are also equal
sector KM = sector KL + sector LM
Sector JN = Sector KM
sector JN = sector KL + sector LM
125 = 6x + 4 + 8x + 9
125 = 14x + 13
14x = 125 - 13
14x = 112
x = 8
sector KL = 6x + 4
= 6(8) + 4 = 48 + 4 = 52
Therefore, the sector KL is 52
To learn more about circle refer here
brainly.com/question/24375372
#SPJ9
Answer:
19
Step-by-step explanation:
9+10=19
