Answer:
The volume of the cavity is 0.013m^3
Explanation:
To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:
Step one:
Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.
Volume of the cylinder = 2.1 / 11.053 =0.19
Step two:
From the volume of the cylinder, we can get the radius of the cylinder.

Step three:
From the cross-sectional area, we can obtain the radius of the cavity.
Let the radius of the cavity be = r, while the radius of the cylinder be = R
CSA of cavity =

Step Four:
calculate the volume of the cavity using volume =
Recall that the cavity has the same height as the original cylinder

... low frequency and high amplitude.
If the satellite doesn't have little rocket engines or other thrusters on it, AND it stays far enough from Earth that it doesn't have to plow through any air molecules, AND no pieces break off of it and drift away, AND there are no hamsters inside it running on treadmills connected to external thrusters, then there's no way for it to gain or lose energy, and its total energy remains constant.
Some of its energy is always changing, either from potential to kinetic or from kinetic to potential, as its distance from Earth changes. But the total stays constant.
Answer:
a. 12 m/s² down
Explanation:
Acceleration has units of length per time squared. Acceleration is a vector, so it also has a direction.
Answer:
The angle of diffraction are 67.75 deg and 53.57 deg.
Explanation:
Given:
Davisson and Germer experiment with nickel target for electrons bombarding.
Voltages :
and
We have to find the angles that is
and
.
Concept:
- Davison Germer experiment is based on de Broglie hypothesis where it says matter has both wave and particle nature.
- When electrons get reflected from the surface of a metal target with an atomic spacing of
, they form diffraction patterns. - The positions of diffraction maxima are given by
. - An atomic spacing is
, when the principal maximum corresponds to n=1 - The wavelength is
, and
.
Solution:
Finding the wavelength at
.
⇒ 
⇒
nm
Plugging the values of wavelength.
⇒
⇒
⇒
degrees.
Now
For for the electrons with energy
,
the wavelength is.
⇒
nm
And
⇒
degrees.
So,
The angles of diffraction maxima are 67.75 deg and 53.57 deg.