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Ilia_Sergeevich [38]
3 years ago
14

What increases the amount of light that bends passing through a lens

Physics
2 answers:
BartSMP [9]3 years ago
4 0

Answer:

The answer is a. Greater curve

KatRina [158]3 years ago
3 0
A. a greater curve
 just took the test
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How many matters can a sound wave travel through​
luda_lava [24]

Sound waves travel through all three states of matter: solids, liquids, and gases.

4 0
4 years ago
A 5.00-kg ball, moving to the right at a velocity of +2.00 m/s on a frictionless table, collides head-on with a stationary 7.50k
valina [46]
Using the law of conservation of momentum:
m₁u₁ + m₂u₂ = m₁v₁ + m₂ v₂; u₂ = 0
5 x 2 = 5v₁ + 7v₂
10 = 5v₁ + 7v₂
v₂ = (10 - 5v₁)/7
Elastic collision so kinetic energy conserved:
1/2 x 5 x 2²  = 1/2 (5v₁² + 7v₂²)
20 = 5v₁² + 7((10 - 5v₁)/7)²
140 = 35v₁² + 5v₁² + 100 - 20v₁
40v₁² - 20v₁ - 40 = 0
v₁ = 1.28 m/s OR v₁ = -0.78 m/s
The first ball is lighter so its velocity will change direction due to collision.
v₁ = -0.78 m/s

10 = 5(-0.78) + 7v₂
v₂ = 1.98 m/s
6 0
3 years ago
Thalia is drafting a plan to move a large, perfect sphere concrete sculpture that is in front of her office building. Describe t
Charra [1.4K]

Answer:She would need to first know the weight of the sculpture and what she is going to move it with then she will need to use newton's second law to calculate the amount of force needed to move it

Explanation: I just did the assignment on edgunity

3 0
3 years ago
Read 2 more answers
A mover pushes a 30 kg crate across a level florr with a force of 250 N, but the crate accelerates at a rate of only 5.83 m/s sq
arlik [135]

Force of friction=75 N

Explanation:

we use Newton's second law of motion

F- Ff= ma

F = applied force=250 N

Ff= force of friction

a= acceleration= 5.83 m/s²

m= mass=30 kg

250- Ff= 30 (5.83)

Ff=250-30(5.83)

Ff=250-175

Ff=75 N

7 0
3 years ago
A 0.2 kg hockey puck moving at 80 m/s is caught by a 40 kg goalie at rest. With what speed does the goalie slide on the slide?
Lady_Fox [76]

Answer:

V = 0.39 m/s

Explanation:

Given that,

Mass of hockey puck, m = 0.2 kg

Mass of goalie = 40 kg

Speed of hockey puck, v = 80 m/s

We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

mv=(M+m)V\\\\V=\dfrac{mv}{M+m}\\\\V=\dfrac{0.2\times 80}{0.2+40}\\\\V=0.39\ m/s

So, the required speed is 0.39 m/s.

5 0
3 years ago
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