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3 years ago

How far can a caterpillar; traveling at 0.06m/s, move in 60 seconds?

Mathematics

1 answer:

nignag [31]3 years ago

4 0

Answer:

3.6 meters in 60 seconds

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The sum of three numbers is 124. The third number is 3 times the first. The second number is 9 more than the first. What are the

Leona [35]

Answer:

23, 32, 69

Step-by-step explanation:

3 numbers x, y, z

z = 3x

y = x + 9

x+y+z=124

x + (x + 9) + 3x = 124

5x + 9 = 124

5x = 115

x = 23

y = 32

z = 69

check: 23 + 32 + 69 = 124

8 0

3 years ago

Th upper-left coordinated on a rectangle are (3, -3) and the upper-right coordinates are (7 -3). The rectangle has an area of 16

Stella [2.4K]

Answer: view picture

Step-by-step explanation:

7 0

3 years ago

The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the

nata0808 [166]

Answer:

Car a travels (300) miles in 6 hours

Car B travels (200) miles in 5 hours

Car A speed is (50) miles per hour

Car B speed is(40) miles per hour.

Car A traveled (faster than) Car B.

The graph for Car A is(steeper than) the graph for Car B

Step-by-step explanation:

$distanc \: = x - y$

where x is starting location and y is the ending location

$speed \: = \frac{distance}{time}$

the rest we see once we have solve for distance and speed of the 2 cars

4 0

3 years ago

What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?

ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$

where

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

- For AB:

$d=\sqrt{[1-(-5)]^{2}+(4-4)^2}$

$d=\sqrt{(1+5)^{2}+(0)^2}$

$d=\sqrt{(6)^{2}}$

$d=6$

- For BC:

$d=\sqrt{(3-1)^{2} +(-4-4)^{2}}$

$d=\sqrt{(2)^{2} +(-8)^{2}}$

$d=\sqrt{4+64}$

$d=\sqrt{68}$

$d=8.24$

- For AC:

$d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}$

$d=\sqrt{(3+5)^{2} +(-8)^{2}}$

$d=\sqrt{(8)^{2} +64}$

$d=\sqrt{64+64}$

$d=\sqrt{128}$

$d=11.31$

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

$p=AB+BC+AC$

$p=6+8.24+11.31$

$p=25.55$

$p=25.6$

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0

4 years ago

For the simple linear equation below, what is the y-coordinate of the ordered pair when the x-coordinate is −5?

NARA [144]

Answer:

-9

Step-by-step explanation:

7 0

3 years ago