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2 years ago

What is the answer to 3-(-8)

Mathematics

2 answers:

Brut [27]2 years ago

8 0

Answer:

Step-by-step explanation:

3 - (-8) = 3 + 8 = 11

ICE Princess25 [194]2 years ago

8 0

Answer: 11

Step-by-step explanation:

This is because when you subtract a negative number from a positive you get a positive (here's a lil trick if you have 2 minuses In a row they become a plus sign) so the answer is 11

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Really Need Help ! ASAP

SCORPION-xisa [38]

Answer:

hope the above solution will help you

5 0

2 years ago

Factor 10c^2-60cd +80d^2

ozzi

$10c^2-60cd +80d^2$

$(2c - 8d) (5c -10d)$

$this \\ is \\ because...$

$2c*5c=10c^2$

$2c * -10d=-20cd \\ -8d*5c=-40cd \\ -20cd-40cd=-60cd$

$-8d * -10d = 80d$

5 0

2 years ago

joe is playing a game with a regular die. If the number that turns up is even he will gain 5 times the number that comes up. If

vladimir1956 [14]

Answer:

he lost 30 points.

since he rolled an odd number, he will lose 10 times the number he rolled. he rolled 3, which means he lost 30 points. you get that by multiplying 3 and 10.

5 0

3 years ago

HELP ME PLEASE . IF YOURE GOOD GEOMETRY HELP

Art [367]

Oh these are easy, I’ll explain.
To start off, the answer is 11.
I got this by subtracting DE (57) and BC (35). You get 22. Then, you divide the result of the subtraction by 2, which is 11.
Let me know if you need me to explain in more depth, and give brainliest if I’m correct tysm.

4 0

2 years ago

Find the PERIMETER of this triangle

olga2289 [7]

First we need to find the missing side, use

$a = \sqrt{ {c}^{2} - {b}^{2} }$
So the missing leg = the sqrt of the hypotenuse squared minus the other leg squared.

Let's substitute the numbers,

$a = \sqrt{ {10}^{2} - {6}^{2} }$
Solve for the squares,

$a = \sqrt{100 - 36}$
Subtract,

$a = \sqrt{64}$
Solve for the root,

$a = 8$
~~

So our missing length is 8.

To find the perimeter of the triangle, simply add all the sides....

~~

$8 + 10 + 6 = 24$

~~

Answer : 24

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

4 0

2 years ago

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