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Alja [10]
3 years ago
7

What is the answer to 6 – 4r = -3r

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0
Let's solve for "r" by bringing them all to one side.
-3r=6-4r
+4r    +4r
r=6
So, r is equal to 6.
loris [4]3 years ago
3 0
So you have to add the like terms together,

6 - 4r = -3r
    +4r   +4r

        6=1r
   Divide 1 to both sides.
       
      6=r

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Algebra 1. please help me. i’m literally struggling , i’ll give an extra 50 points if it’s right and brainliest. - question in p
Arada [10]

Answer:

15x² - 3x - 7

Step-by-step explanation:

(12x² + 2x) - (-3x²+ 5x + 7)

First open the parentheses by applying the distributive property.

To do this, multiply each term you have inside (-3x⅔ + 5x + 7) by -1.

Thus, you would have the following:

12x² + 2x + 3x² - 5x - 7

Add like terms

12x² + 3x² + 2x - 5x - 7

15x² - 3x - 7

6 0
2 years ago
Two trains are traveling towards each other at a constant speed. The trains are currently 714 miles from each other. The speeds
shutvik [7]
55mph.

you can solve it using the equation distance=speed x time

your total distance is 714, and you have 2 trains, one traveling some speed, x, and one traveling x+8, both traveling for 7 hours. 
your equation would look like this
714 = x(7) + (x+8)(7)
and you can then solve for x, which would be 47. this is the speed of the slower train, but 47+8=55 with give you the speed of the faster train. 
6 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
2 years ago
Help please?? If you deposit $750 in an account that pays 8% annual interest compounded continuously, what will the balance be a
Stella [2.4K]
The formula of a continuous compound interest is
A=p e^rt
A the balance?
P present value 750
E constant
R interest rate 0.08
T time 5 years
A=750×e^(0.08×5)
A=1,118.87
7 0
3 years ago
Triangle TRE has vertices T(3,6), R(-3,10), and E(-9,4). Find the coordinates of point M if line TM is a median of triangle TRE
Sergeeva-Olga [200]

Answer:

The coordinate of point M = (-6,7)

Explanation:

The Median of a triangle is a line segment from a vertex to the midpoint of the opposite side of a triangle.

Given: \triangle TRE has vertices T(3,6) , R(-3,10) and E(-9,4).

Here, line TM is a median of triangle TRE where M is the midpoint of RE.

The midpoint of  M of the line segment from R(-3,10)  to E(-9,4) is;

M = (\frac{-3+(-9)}{2}, \frac{10+4}{2}) = ( \frac{-12}{2}, \frac{14}{2} )=(-6,7)

Therefore, the coordinate of point M is, (-6,7).

7 0
2 years ago
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