Answer:
The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Step-by-step explanation:
The three different assembly lines are: A₁, A₂ and A₃.
Denote <em>R</em> as the event that a component needs rework.
It is given that:
Compute the probability that a randomly selected component needs rework as follows:
Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:
Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.
Given:
initial deposit = 45
total deposit = 105
w = weekly deposit
x = no. of weeks = 5 weeks
y = amount in dollars
45 + 5w = 105
45 + 5w = 105
5w = 105 - 45
5w = 60
w = 60/5
w = $12 weekly deposit.
y = $45 + $12x
<span>x = (y - 45)/12
</span>To check:
y = 45 + 12(5)
y = 45 + 60
y = 105 total deposit in 5 weeks
x = (105-45)/12
x = 60/12
x = 5 weeks
I hope this help
Answer:
SSS, UVD, the answer is D
Step-by-step explanation:
90/9 = 10
70/7 = 10
80/8 = 10
triangle LMN congruent triangle UVD
Ok any more details or is that the question?
Answer:
116 cm²
Step-by-step explanation:
The area of a circle = πr² ← r is the radius
shaded area = external area - internal area
= π × 6.5² - π × 2.3²
= π( 42.25 - 5.29)
= π × 36.96 ≈ 116 cm²
