Answer:
- horizontally compressed by a factor of 2 and translated upward by 3 units.
Step-by-step explanation:
A multiplier of x in a function transformation is effectively a compression factor. That is f(2x) will have half the horizontal extent of f(x) for the same values of x.
Addition of a constant the the value of a function effectively translates the graph upward by that amount. The graph of y = log(2x) +3 has been translated upward 3 units.
The graph of y=log(x) has been horizontally compressed and translated upward to produce the graph of y = log(2x) +3.
Anything Multiplied by 0 will be 0
To complete this equation, it is vital to know the slope. To find the slope using points, you subtract the first x from the second, and the first y from the second. This gives you a slope of 4. Then, you must follow point-slope form and choose one of the order pairs to use. You then write y then the negative of your number. Since the number is already negative, you turn it into a positive. On the other side of the "=" sign, you write your slope, 4 distributing to x. Then you write the negative of your x value. Since it is already negative, it turns into a positive. This gives you a final answer of y+1=4(x+2). I realize that this doesn't line up with your fill-in-the-blank answer, so I am sorry if it doesn't work.
The answer is 3.6. Hope this helps!
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
