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Sidana [21]
3 years ago
9

To improve air quality and obtain a useful product, chemists often remove sulfur from coal and natural gas by treating the conta

minant hydrogen sulfide with O2:
2H2S(g) + O2(g) = 2S(s) + 2H2O(g)


What happens to


a) [H2O] if O2 is added?


b) [H2S] if O2 is added?


c) [O2] if H2S is removed?


d) [H2S] if sulfur is added?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

1) Increase

2) Decreases

3) increases

4) Increase

Explanation:

These questions can only be answered by considering the principle which states that, "When a constraint such as a change in concentration, pressure or volume is imposed on a reaction system in equilibrium. The system will readjust itself in order to annul the constraint."  

Now, if more reactants are added, the equilibrium position will shift towards the right, If more products are added, the equilibrium position will shift to the left.

Similarly, the removal of H2S causes the O2 concentration to increase since the equilibrium position now shifts to the left.

Also, addition of O2 causes H2S to be removed as the equilibrium moves to the right.

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Match each subscript symbol to its correct meaning. <br> Gas b. Liquid c. Aqueous solution
son4ous [18]


solid

s

liquid

l

gas

g

aqueous solution

aq

Hope that helps! :D
5 0
3 years ago
Read 2 more answers
PLEASE HELP<br> I will mark brianliest
Stells [14]

Answer:

I feel A I am not you sure though. could also be D

8 0
3 years ago
Read 2 more answers
Which molecular solid would have the highest melting point?
TEA [102]

Answer:

Choice B. The solid with hydrogen bonding.

Assumption: the molecules in the four choices are of similar sizes.

Explanation:

Molecules in a molecular solid are held intact with intermolecular forces. To melt the solid, it is necessary to overcome these forces. The stronger the intermolecular forces, the more energy will be required to overcome these attractions and melt the solid. That corresponds to a high melting point.

For molecules of similar sizes,

  • The strength of hydrogen bonding will be stronger than the strength of dipole-dipole attractions.
  • The strength of dipole-dipole attractions (also known as permanent dipole) will be stronger than the strength of the induced dipole attractions (also known as London Dispersion Forces.)

That is:

Strength of Hydrogen bond > Strength of Dipole-dipole attractions > Strength of Induced dipole attractions.

Accordingly,

Melting point due to Hydrogen bond > Melting point due to Dipole-dipole attractions > Melting point due to Induced Dipole attractions.

  • Induced dipole is possible between all molecules.
  • Dipole-dipole force is possible only between polar molecules.
  • Hydrogen bonds are possible only in molecules that contain \rm H atoms that are bonded directly to atoms of \rm F, \rm O, or \rm N.

As a result, induced dipoles are the only force possible between molecules of the solid in choice C. Assume that the molecules are of similar sizes, such that the strengths of induced dipole are similar for these molecules.

Melting point in choice B > Melting point in choice D > Melting point in choice A and C.

8 0
3 years ago
Burning 1 kg of coal releases about 3 million joules of energy. If you could use all of the chemical energy to lift another kilo
Katarina [22]

I could lift 3.06 x 10⁵ m high

<h3>Further explanation </h3>

Energy is the ability to do work. Energy can change from one energy to another

Potential energy is the energy that an object has because of its position

The potential energy can be formulated:

Ep = m. g. h

E = potential energy of an object, joule

m = object mass, kg

g = gravity acceleration, m / s²

h = height of an object, m

energy of coal = 3.10⁶ J

mass = 1 kg

g = 9.8 m/s²

\tt h=\dfrac{E}{m.g}\\\\h=\dfrac{3.10^6}{1\times 9.8}=3.06\times 10^5`m

5 0
3 years ago
Imagine a balloon is made from a membrane that's permeable to water but not sucrose molecules. How would the balloon be affected
Arlecino [84]

Answer:

The balloon would get larger as it gains water

Explanation:

Due to the process of osmosis, water molecules would passively move from an area of lower solute concentration, the water in the beaker, to an area of higher solute concentration, inside the balloon.

8 0
4 years ago
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