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Lapatulllka [165]
3 years ago
14

Which molecular solid would have the highest melting point?

Chemistry
1 answer:
TEA [102]3 years ago
8 0

Answer:

Choice B. The solid with hydrogen bonding.

Assumption: the molecules in the four choices are of similar sizes.

Explanation:

Molecules in a molecular solid are held intact with intermolecular forces. To melt the solid, it is necessary to overcome these forces. The stronger the intermolecular forces, the more energy will be required to overcome these attractions and melt the solid. That corresponds to a high melting point.

For molecules of similar sizes,

  • The strength of hydrogen bonding will be stronger than the strength of dipole-dipole attractions.
  • The strength of dipole-dipole attractions (also known as permanent dipole) will be stronger than the strength of the induced dipole attractions (also known as London Dispersion Forces.)

That is:

Strength of Hydrogen bond > Strength of Dipole-dipole attractions > Strength of Induced dipole attractions.

Accordingly,

Melting point due to Hydrogen bond > Melting point due to Dipole-dipole attractions > Melting point due to Induced Dipole attractions.

  • Induced dipole is possible between all molecules.
  • Dipole-dipole force is possible only between polar molecules.
  • Hydrogen bonds are possible only in molecules that contain \rm H atoms that are bonded directly to atoms of \rm F, \rm O, or \rm N.

As a result, induced dipoles are the only force possible between molecules of the solid in choice C. Assume that the molecules are of similar sizes, such that the strengths of induced dipole are similar for these molecules.

Melting point in choice B > Melting point in choice D > Melting point in choice A and C.

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3 years ago
7. What volume of a 0.10 mol/l HCl solution is needed to neutralize 10 ml of a 0.15
svp [43]

Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is LiOH.

We are given:

n_1=1\\M_1=0.10mol/L\\V_1=?mL\\n_2=1\\M_2=0.15mol/L\\V_2=10mL

Putting values in above equation, we get:

1\times 0.10\times V_1=1\times 0.15\times 10\\\\V_1=15mL

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

5 0
4 years ago
What pressure (in kilopascals) is exerted by 4.20 moles of Xenon gas in a 15.0 L container at 280.0 K?
aniked [119]

Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa

Explanation:

The question requires us to calculate the pressure, in kPa, connsidering the following information:

<em>number of moles = n = 4.20mol</em>

<em>volume of gas = V = 15.0L</em>

<em>temperature of gas = T = 280.0 K</em>

We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:

PV=nRT\rightarrow P=\frac{nRT}{V}

Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:

<em>R = 8314.46 L.Pa/K.mol</em>

Applying the values given by the question to the rearranged equation above, we'll have:

\begin{gathered} P=\frac{nRT}{V} \\  \\ P=\frac{(4.20mol)\times(8314.46L.Pa/K.mol)\times(280.0K)}{(15.0L)}=652\times10^3Pa \end{gathered}

Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.

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