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mixas84 [53]
3 years ago
12

Double replacement reactions in total ionic equation form

Chemistry
1 answer:
dem82 [27]3 years ago
7 0
N
a
2
S
O
4
(
a
q
)
+
B
a
(
N
O
3
)
2
(
a
q
)
→
B
a
S
O
4
(
s
)
+
2
N
a
N
O
3
(
a
q
)
Break up the compounds into ions from which they came and cross out the ones that appear on both sides; those are your
spectator ions
.
2
N
a
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
+
2
N
a
+
(
a
q
)
+
2
N
O
−
3
(
a
q
)
Barium sulfate
is insoluble so it doesn't ionize in solution
Write net ionic equation
S
O
2
−
4
(
a
q
)
+
B
a
2
+
(
a
q
)
→
B
a
S
O
4
(
s
)
⏐
⏐
↓
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How far does light travel in 3.0 days
MArishka [77]

Answer:

d=7.77\times 10^{13}\ m

Explanation:

We know that the speed of light is equal to 3\times 10^8\ m/s

We need to find how far the light travel in 3 days.

Speed of an object is equal to distance covered divided by time taken.

Also, 1 day = 86400 s

3 days = 259200 s

So,

d=vt

d=3\times 10^8\times 259200\\\\d=7.77\times 10^{13}\ m

So, the light will travel 7.77\times 10^{13}\ m in 3 days.

7 0
3 years ago
6. Find the partial pressures of the gases in a mixture with a total pressure of 101.3 kPa, if there are 7.8 mole of
ikadub [295]

Answer:

Explanation:

Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10

the partial pressures of the gases in a mixture

= mole fraction x Total pressure

mole fraction = mole of a gas in the mixture  / total mole

partial pressure of Ng = \frac{7.8}{10} \times 101.3 kPa

= 79.014 kPa

partial pressure of O = \frac{2.1}{10} \times 101.3 kPa

= 21.273 kPa .

partial pressure of  Ar = \frac{.09}{10} \times 101.3 kPa

= .9117 kPa .

partial pressure of  Co = \frac{.01}{10} \times 101.3 kPa

= .1013 k Pa .

3 0
3 years ago
In which of the following is light energy converted to electrical energy
AleksandrR [38]
The answer is c.solar cell
4 0
4 years ago
Read 2 more answers
PLZ HELP For the reaction: 2NO2(g) → N2O4(l),
Furkat [3]

Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

\Delta H=-20kJ/mol-(+66kJ/mol)

6 0
3 years ago
| | | |<br> | | | |<br> | | | |<br> VVV
zubka84 [21]

Answer:the answer would be a because that's what it would talk about and is the correct answer

Explanation:yes it is correct just answer it trust me

7 0
4 years ago
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