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Mnenie [13.5K]
3 years ago
12

PLEASE HELP ME ON THIS ALGEBRA PROBLEM!!!

Mathematics
1 answer:
dexar [7]3 years ago
8 0
<h3><em>y(1)=(-1)3+3x(-1)-(-1)-3</em></h3><h3><em>=-1-3+1-3</em></h3><h3><em>=-6</em></h3><h3><em>y=-6</em></h3><h3><em>x=-1</em></h3>

<em></em>

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A cube has a surface area of 3/2. What's the volume?
Cloud [144]

Answer:

C

Step-by-step explanation:

Assume the surface area = 6x²

6 is the number of faces and x is the length of the cube

so 3/2 = 6x²

Divide by 6

1/4 = x²

Square root both sides

1/2 = x

Volume is : l×w×h

so 1/2 × 1/2 × 1/2 = 1/8

5 0
3 years ago
Read 2 more answers
PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!
Deffense [45]

Answer:23

Step-by-step explanation:

8 0
2 years ago
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1. One week Carlos bought 3 bags of Tabitha Tidbits and 4 bags of Figaro Flakes for $43.00. The next week he bought 3 bags of Ta
d1i1m1o1n [39]
Tabitha Tidbits costs $7 per bag, and Figaro Flakes is $5.50 per bag.
You need to set up a system of equations. Use "x" for Tabitha Tidbits and "y" for Figaro Flakes, and let the total cost of each trip equal c. Using the equation ax+by=c, substitute the cost of each trip in for c, and the number of bags for each food for a and b respectively. The two equations will be:
3x+4y=43
3x+6y=54
Isolate x in the first equation and you will get:
x=(43-4y)/3
Substitute the above equation for x into the other equation:
3*((43-4y)/3)+6y=54
Isolate y in this equation, and you will get 11/2, which is 5.5
So the cost of one bag of Figaro Flakes is $5.50
Now substitute this into the equation where you isolated x:
(43-4(5.5))/3
You will get x=7, so a bag of Tabitha Tidbits is $7
3 0
3 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
(4x-1) /2=x+7<br>4x-1 all over 2 = x +7​
Damm [24]

Answer:

x = \frac{15}{2}

Step-by-step explanation:

Given

\frac{4x-1}{2} = x + 7 ( multiply both sides by 2 to clear the fraction )

4x - 1 = 2(x + 7) ← distribute

4x - 1 = 2x + 14 ( subtract 2x from both sides )

2x - 1 = 14 ( add 1 to both sides )

2x = 15 ( divide both sides by 2 )

x = \frac{15}{2}

7 0
3 years ago
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