PLEASE HELP ME ON THIS ALGEBRA PROBLEM!!!

Mathematics

1 answer:

dexar [7]3 years ago

8 0

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practice counting in 2's , 5's and 10's, starting on 0. whats patterns do you notice ? can you write sentences to explain these

Mice21 [21]

When you multiply 5 by 1 you get 5. When you multiply 5 by 2 you get 10. If you keep doing this, you get a list of multiples of 5.

5
10
15
20
25
30
35
40
45
50

All of these numbers end in either 5 or 0. We can do the same with 2's and 10's.

2
4
6
8
10
12
14
16
18
20

For all 2's we can see that they are all even and end with an even number (0,2,4,6,8)

10
20
30
40
50
60
70
80
90
100

For 10's we can see that they all end in 0.

7 0

3 years ago

HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x

Anna35 [415]

$\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0$

$\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}$