Subtract 3y and move it to the right
X= 1 - 3Y
The answer is 3x^2 + 19x - 12.
Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
Answer:
aprox. 100.94
Step-by-step explanation:
Answer:
15 kg
Step-by-step explanation:
Radius of a solid sphere : mass of a solid sphere
3 cm : 9 kg
Find the mass of a sphere of the same material of radius 5 cm
Radius of a solid sphere : mass of a solid sphere
5 cm : x kg
Equate both ratios to find x
3 cm : 9 kg = 5 cm : x kg
3/9 = 5/x
3 * x = 9 * 5
3x = 45
x = 45/3
x = 15 kg
The mass of a sphere of the same material of radius 5 cm is 15 kg