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Wittaler [7]
4 years ago
7

Bob and Mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum

of the ages of his children. Mark points out that there is still not enough information to accurately guess. Finally, Bob says, "My youngest child called Justice." Mark can then correctly determine the ages of Bob's children. What are the ages?
Mathematics
1 answer:
DaniilM [7]4 years ago
6 0
I have answered this question before. 

Given:
Bob has three kids whose ages has the product of 72. I will only be able to give you a set of 3 numbers to represent the ages. Had the sum of the ages been given, the specific ages would be provided.

I just did a prime factorization of 72.

72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 =   9
  9 ÷ 3 =   3
  3 ÷ 3 =   1

1 x 2 x 2 x 2 x 3 x 3 = 72   ⇒ 2³ x 3²

There are a lot of possible combinations, here are a few.

1 x 8 x   9 = 72      ⇒ 1 + 8 + 9 = 18
1 x 4 x 18 = 72      ⇒ 1 + 4 + 18 = 23
<span>2 x 4 x   9 = 72      ⇒ 2 + 4 + 9 = 15</span>
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Sedaia [141]

Answer:

The "3y" in the first term is a factor

The "9" in the second term is a coefficient

The "(7 + 2x)" in the first term is a factor

Step-by-step explanation:

Given in the question an expression

3y(7 + 2x) + 9xy - 10

  1. The coefficients are the numbers that multiply the variables, x and y.
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6 is coefficient

    2.Constants are terms without variables

<h3>Example</h3>

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(4x+1)(3x+7)

(4x+1) and (3x+7) both are factors

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If $6500 is invested at a rate of 6% compounded continuously, find the balance in the account after 3 years
Alex787 [66]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6500\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &3 \end{cases} \\\\\\ A=6500e^{0.06\cdot 3}\implies A=6500e^{0.18}\implies A\approx 7781.91

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arc GH = 74°

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The inscribed angle GFH is half the measure of the intercepted arc aGH, then

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25 33 39 40 41 41 45 46 48 49 51 52 67 73 79

46 is at the center-> median
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25 33 39 40 41 41 45
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48 49 51 52 67 73 79
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Q1-1.5*IQR=40-1.5*12=40-18=22
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4 + 6 (3) + 2(5 1/2 - 1)
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