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olganol [36]
3 years ago
13

A circular piece of glass has a radius of 0.8 meters. The glass sells for $4.60 per square meter. What is the total cost of the

circular piece of glass?
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

Given radius of circle = 0.8 meters

Area of circle = pi * r*r

Area =3.14 * 0.8 *0.8 = 2.0096 meter square

Cost of one square meter of glass = $4.60

cost of 2.0096 square meter of glass = 4.60*2.0096 = 9.24416

Cost of glass = $9.24416

Mama L [17]3 years ago
5 0

Here given that r= 0.8

Area of circular glass = area of circle = pi r^2

= 3.14 ( 0.8)^2 = 2.009 square meter

cost of one square meter = 4.60

cost of 2.009 square meter = 4.60 * 2.009 = 9.244

Answer $ 9.244 .

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Mean of the integers 8,-11,18,-8,-3
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Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
3 years ago
A.) If m 1 = 3x - 7, find x.
aleksley [76]

Answer:

x = 25

Step-by-step explanation:

Angle 1 and the angle opposite from Angle 1 (the angle that's 68°) are vertical angles.

What are vertical angles, you ask?

According to the Oxford dictionary, vertical angles are each of the pairs of opposite angles made by two intersecting lines.

For example, take the letter X. The letter X has two lines that intersect to form 4 angles. The top and bottom angles are a pair of vertical angles. So are the left and right angles.

Vertical angles are always congruent.

(This is VERY important to know! It will help you solve many types of geometry problems!)

m1 is 3x - 7. Because Angle 1 and the angle that's 68° are vertical angles, that means they are equal to each other.

Therefore: 3x - 7 = 68.

Now, you can solve for x to get x = 25.

Hope this helps!

3 0
3 years ago
Question 2
julia-pushkina [17]

Answer:

A. C = (d-ab)/a

Step-by-step explanation:

a(c + b) = d

a(c + b)/a = d/a

c + b = (d/a)

c = (d/a) - b

a(c + b) = d

ac + ab = d

ac = d - ab

ac/a = d/a - ab/a

c = (d/a) - b

5 0
3 years ago
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