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VikaD [51]
3 years ago
15

Which of these statements regarding mobile games is true? A. They are typically played indoors. B. They have detailed environmen

ts. C. Their levels can be completed quickly. D. They are typically played for several hours at a time. E. They are played on large screens.
game development
Computers and Technology
2 answers:
natulia [17]3 years ago
4 0

Answer:

a

Explanation:

Margarita [4]3 years ago
3 0

Answer:

c

Explanation:

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The bond spread in an interactive is a chart that is used to compare and chart the current spread between the corporate bond as well as the benchmark government bond.

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4 years ago
Read 2 more answers
find_cow(name, cows) Given a name and a Python list of Cow objects, return the Cow object with the specified name. If no such Co
nadya68 [22]

Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

<h3>Writting the code in python:</h3>

<em>def load_cows(filename):</em>

<em>      cow_dict = dict()</em>

<em>    f = open(filename, 'r')</em>

<em> </em>

<em>    for line in f:</em>

<em>        line_data = line.split(',')</em>

<em>        cow_dict[line_data[0]] = int(line_data[1])</em>

<em>    return cow_dict</em>

<em>def greedy_cow_transport(cows, limit=10):</em>

<em>       trips = []</em>

<em>    cowsCopy = cows.copy()</em>

<em>    sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)</em>

<em>    while sum(cowsCopy.values()) > 0:</em>

<em>        ship = []</em>

<em>        total = 0</em>

<em>        for cow, value in sortedCows:</em>

<em>            if cowsCopy[cow] != 0 and value + total <= limit:</em>

<em>                ship.append(cow)</em>

<em>                total += value</em>

<em>                cowsCopy[cow] = 0</em>

<em>        trips.append(ship)</em>

<em>    return trips</em>

<em>def brute_force_cow_transport(cows,limit=10):</em>

<em>     trips = []</em>

<em>     possibilities = []</em>

<em>    for i in power_list:</em>

<em>        ship = []</em>

<em>        for j in i:</em>

<em>            ship_weights = []</em>

<em>            for k in j:</em>

<em>                ship_weights.append(cows[k])</em>

<em>                #print(ship_weights)</em>

<em>            ship.append(sum(ship_weights))</em>

<em>            #print(ship)</em>

<em>        if all(d <= limit for d in ship):</em>

<em>            possibilities.append(i)</em>

<em>      pruned_possibilities = []</em>

<em>    for k in possibilities:</em>

<em>        if k not in pruned_possibilities:</em>

<em>            pruned_possibilities.append(k)</em>

<em>    # now find the minimum list length:</em>

<em>    min_list_len = min(map(len, pruned_possibilities))</em>

<em>    for l in pruned_possibilities:</em>

<em>        if len(l) == min_list_len:</em>

<em>            return l</em>

<em>       </em>

<em>def compare_cow_transport_algorithms():</em>

<em>       greedy_start = time.time()</em>

<em>    greedy_results = greedy_cow_transport(cows, limit = 10)</em>

<em>    greedy_end = time.time()</em>

<em>    print('Greedy Algorithm time:', greedy_end -greedy_start)</em>

<em>    brute_force_start = time.time()</em>

<em>    brute_force_results = brute_force_cow_transport(cows, limit = 10)</em>

<em>    brute_force_end = time.time()</em>

<em>    print('Brute force time:', brute_force_end - brute_force_start)</em>

<em>    print('Greedy Algorithm results:', greedy_results)</em>

<em>    print('Number of trips returned by Greedy Algorithm:', len(greedy_results))</em>

<em>    print('Brute Force Algorithm results:', brute_force_results)</em>

<em>    print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))</em>

   

See more about python at brainly.com/question/13437928

#SPJ1

4 0
2 years ago
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