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ASHA 777 [7]
3 years ago
10

An organized file title helps save time locating files, communicates professionalism, and lets us know the file is most likely N

OT a virus. True False
Computers and Technology
1 answer:
Shkiper50 [21]3 years ago
6 0

An organized file title helps save time locating files, communicates professionalism, and lets us know the file is most likely not a virus: True.

A file can be defined as a computer document or resource which avails an end user the ability to store (record) data as a single unit on the storage device of a computer system.

Generally, all files are identified and organized based on the following criteria:

  • Name (Title).
  • Format (Type).
  • Size.
  • Date.
  • Status.
  • Owner.
  • Permission.

Based on the aforementioned criteria, an organized file title would help to save time locating files, communicates professionalism, and lets us know the file is most likely not a virus because it must have been scanned with an antivirus utility.

Read more: brainly.com/question/23728214

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Answer:

Explanation:

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import java.util.Arrays;

class Brainly {

   public static void main(String[] args) {

       int[] seq1 = createSequence(5, 4, 2);

       int[] seq2 = createSequence(5, 3, 3);

       System.out.println("Winner: " + Arrays.toString(compareSequences(seq1, seq2)));

   }

   public static int[] createSequence(int num, int upperEnd, int lowerEnd) {

       int[] myArray = new int[num];

       int middle = (int) Math.floor(num/2.0);

       myArray[0] = upperEnd;

       myArray[num-1] = lowerEnd;

       int currentValue = upperEnd;

       for (int i = 1; i < num-1; i++) {

           if (i <= middle) {

               myArray[i] = currentValue + 1;

               currentValue += 1;

           } else {

               myArray[i] = currentValue - 1;

               currentValue += 1;

           }

       }

       System.out.println(Arrays.toString(myArray));

       if (myArray[num-2] < lowerEnd) {

           System.out.println("-1");

           int[] empty = {};

           return empty;

       } else {

           return myArray;

       }

   }

   public static int[] compareSequences(int[] seq1, int[] seq2) {

       int lowestLength;

       if (seq1.length > seq2.length) {

           lowestLength = seq2.length;

       } else {

           lowestLength = seq1.length;

       }

       for (int i = 0; i < lowestLength; i++) {

           if (seq1[i] > seq2[i]) {

               return seq1;

           } else if (seq1[i] < seq2[i]) {

               return seq2;

           }

       }

       if (seq1.length > seq2.length) {

           return seq1;

       } else {

           return seq2;

       }

   }

}

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