108 / 1376 is the probability that a student participates in both sports and music.
<u>Step-by-step explanation:</u>
It is given that,
A suburban high school has a population of 1376 students.
- Let the event A be the no.of students participated in sports.
- Let the event B be the no.of students participated in music.
The number of students who participate in sports is 649.
The number of students who participate in music is 433.
<u>To find the probability of event A (sports) :</u>
P(sports) = No.of students participated in sports / Total students.
⇒ 649 / 1376
∴ P(A) = 649 / 1376
<u>To find the probability of event B (music) :</u>
P(music) = No.of students participated in music / Total students.
⇒ 433 / 1376
∴ P(B) = 443 / 1376
From the question, we know that the probability that a student participates in either sports or music is 974 /1376.
∴ P(A∪B) = 974 / 1376
<u>To find the probability that a student participates in both sports and music :</u>
The formula used here is,
P(A∩B) = P(A) + P(B) - P(A∪B)
⇒ 649 / 1376 + 433 / 1376 - 974 /1376
⇒ 108 / 1376
∴ P(A∩B) = 108 / 1376
Answer:
50 degrees
Step-by-step explanation:
The 40⁰ angle is bisecting a right, or 90⁰ angle. The total of angles f and 40⁰ = 90⁰
f + 40⁰ = 90⁰
f = 50⁰
<span>1/8 + 2(1/2m + 5) = 1/4m + 7 would equal m=-25/6</span>
Answer:
- 4x² + 6x - 3 remainder -12
Step-by-step explanation:
<u>Given:</u>
- (x) = 8x³ + 16x² − 15
- g(x) = 2x + 1
<u>To find:</u>
<u>Use long division:</u>
- (8x³ + 16x² − 15) / (2x + 1)
2x + 1 | (8x³ + 16x² − 15
<u>| 8x³ + 4x²</u>
12x² + 0x - 15
<u>12x² + 6x</u>
-6x - 15
<u>-6x - 3</u>
-12
4x² + 6x - 3 remainder -12
Answer:
30
Explanation:
count from -5 all the way to 25
