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Tpy6a [65]
4 years ago
13

5x+20y=4 x=-4y+1 Solve for x/y

Mathematics
1 answer:
Andrews [41]4 years ago
6 0

Hi there!


Looks like a lot of work is going on here.


Let's start by solving this equation for the x.


5x + 20y = 4


Step 1) Add -20y to both sides.


5x + 20y + - 20y = 4 - 20y 5x = -20y + 4


Step 2) Divide both sides by 5.


\frac{5x}{5}  = \frac{-20y + 4}{5}


x = -4y +  \frac{4}{5}


Final Answer:


x = -4y +  \frac{4}{5}


Now, let's solve for y.


Step 1) Add -5x to both sides.


5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4


Step 2) Divide both sides by 20.


\frac{20y}{20} =  \frac{-5x + 4}{20}


y =  \frac{-1}{4} x +  \frac{1}{5}


Final Answer:


y =  \frac{-1}{4} x +  \frac{1}{5}


Hope this helps! :D


Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

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Answer:

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(b)

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(c)

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Explanation has given below.

Step-by-step explanation:

Solution:

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   = B (2; 5, 0.94)

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(d)  Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?

Given:

h = 25000

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m = Bit (25000, 0.06)

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m = Bit (25000, 0.01)

E(m) = 25000 x 0.010

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