All categories

3 years ago

The point slope from the equation below that represents the line that passes through the point (-1, 6) and has a slope of -3

Mathematics

1 answer:

SVEN [57.7K]3 years ago

8 0

Y-6 = -3(x+1)

y-6= -3x-3

y= -3x+3 is the answer to the question

You might be interested in

Find g[h(x)] if g(x)=x^2 and h(x)=x+3

svetlana [45]

Answer:

g(h(x)) = [x + 3]^2 or x^2 + 6x + 9

Step-by-step explanation:

g[h(x)] signifies that h(x) is the input to g(x).

Writing out g(x) = x^2 and replacing "x" with [x + 3], we get:

g(h(x)) = [x + 3]^2 or x^2 + 6x + 9

8 0

2 years ago

Please help (Geometry)<br> (click to see the whole thing)

omeli [17]

Answer:

Step-by-step explanation:

If we know that D is the midpoint, then 2x + 7 = 4(x-3). Doing the algebra on that gives us

2x + 7 = 4x - 12 and

19 = 2x so

x = 9.5

8 0

2 years ago

What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?

IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

$(x^3-3x^2+5x-3)\div (x-1)$

To find:

The quotient.

Solution:

We have,

$(x^3-3x^2+5x-3)\div (x-1)$

It can be written as

$=\dfrac{x^3-3x^2+5x-3}{x-1}$

Splitting the middle terms, we get

$=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}$

$=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}$

Taking out the common factor (x-1), we get

$=\dfrac{(x-1)(x^2-2x+3)}{x-1}$

Cancel the common factors.

$=x^2-2x+3$

The quotient is $x^2-2x+3$ .

Therefore, the correct option is D.

7 0

2 years ago

Read 2 more answers

Can you please help me

asambeis [7]

C. Hope this helps:)

8 0

3 years ago

If u do 3 I’ll mark Brainlynest u don’t have to do 3 it depends but also 14 points

Helen [10]

Answer:

Step-by-step explanation:

A(-5,-2),B(-2,-2), C(-5,2)

find distance first:d=√(x2-x1)^2+(y^2-y1^2)

AB: 3

BC: 5

AC: 4

perimeter of triangle=3+5+4=12

compliment angle=90

90+34=124

5x+17+x+19=180

x=24

4 0

3 years ago