3 years ago

What is the value of 12 more than the quiotent of a number of and two decreased by 4 when n is 4

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

Answer:

Step-by-step explanation:

"12 more than the quiotent of a number n of and two decreased by 4"

$\left(\dfrac{n}{2}-4\right)+12$

Simplify:

$\left(\dfrac{n}{2}-4\right)+12=\dfrac{n}{2}-4+12=\dfrac{n}{2}+8$

Put n = 4 to the expresssion:

$\dfrac{4}{2}+8=2+8=10$

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Factor:<br><br><br>(m+2)^2−(m+2)+mn·(n+2)+2n(n+2)

bazaltina [42]

ANSWER
${(m + 2)}( {n}^{2} + 2n + m + 1)$

EXPLANATION

The given expression is

${(m + 2)}^{2} - (m + 2) + mn(n + 2) + 2n(n + 2)$

We factor to get,

$= {(m + 2)}(m + 2 - 1) +n (n + 2) (m+ 2)$

This implies that,

$= {(m + 2)}(m + 1) +n (n + 2) (m+ 2)$

We factor further to obtain,

$= {(m + 2)}((m + 1) +n (n + 2))$

or

$= {(m + 2)}( {n}^{2} + 2n + m + 1)$