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3 years ago

What is the value of 12 more than the quiotent of a number of and two decreased by 4 when n is 4

Mathematics

1 answer:

liberstina [14]3 years ago

4 0

Answer:

Step-by-step explanation:

"12 more than the quiotent of a number n of and two decreased by 4"

$\left(\dfrac{n}{2}-4\right)+12$

Simplify:

$\left(\dfrac{n}{2}-4\right)+12=\dfrac{n}{2}-4+12=\dfrac{n}{2}+8$

Put n = 4 to the expresssion:

$\dfrac{4}{2}+8=2+8=10$

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Under his cell phone plan, Liam pays a flat cost of $69.50 per month and $5 per gigabyte. He wants to keep his bill under $90 pe

natulia [17]

Answer:

5y+69.50<90

Step-by-step explanation:

You can think of the number of gigabytes he will use as "y", since we don't know the number of gigabytes he will use. The flat cost of one month is $69.50.

You need to add those to calculate the complete cost. The inequality would use a less than sign because he needs to pay less than $90/month. It would not use an inequality sign with a line under it because the problem doesn't say he wants to use $90 or less.

You would solve using basic computation (subtraction and division). Hope this helped!

3 0

1 year ago

Find the value of x in the given figure using properties of parallel lines. answers: A) 35° B) 15° C) 75° D) 105°

Harlamova29_29 [7]

Answer:

75 degrees

Step-by-step explanation:

those two angles = 180

180-105 =75

8 0

2 years ago

Read 2 more answers

Y=x(x−2)^3 identify the zeros and their multiplicities.

lawyer [7]

The zeros of the function are 0 and 2
The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

<h3>Zeros and multiplicities of functions</h3>

Given the function $y=x(x-2)^3$

The zeros of the function is at the point where y = 0

$x(x-2)^3 =0\\x = 0\\(x-2)^3=0\\x-2=0\\x=2$

Hence the zeros of the function are 0 and 2

The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

Learn more on zeros and multiplicity here: brainly.com/question/11314797

6 0

2 years ago

in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver

snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

$Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} } }$

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

= 0.000 (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

To learn more about hypothesis click here:

brainly.com/question/17173491

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5 0

1 year ago

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]