Question

What is the value of 12 more than the quiotent of a number of and two decreased by 4 when n is 4

Answer 1

Answer:

10

Step-by-step explanation:

"12 more than the quiotent of a number n of and two decreased by 4"

$\left(\dfrac{n}{2}-4\right)+12$

Simplify:

$\left(\dfrac{n}{2}-4\right)+12=\dfrac{n}{2}-4+12=\dfrac{n}{2}+8$

Put n = 4 to the expresssion:

$\dfrac{4}{2}+8=2+8=10$