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3 years ago

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False

Mathematics

1 answer:

swat323 years ago

8 0

Answer:

True

Step-by-step explanation:

We can plug in and see.

If (3,0) is on the graph of P, then P(3) will evaluate to 0.

Let's try it:

P(3)=(3)^3-7(3)^2+15(3)-9

P(3)=27-7(9)+45-9

P(3)=27-63+45-9

P(3)=-36+45-9

P(3)=9-9

P(3)=0

Since P(3)=0, then (3,0) is an ordered pair of P.

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Answer:

$95.5090 must be deposited monthly

Step-by-step explanation:

From the information given:

The annual interest rate (r) = 4.2% = 0.042

Let assume that an amount Y is deposited, then after one month, it will increase to:

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$= Y ( 1+ \dfrac{0.042}{12})^{48}+Y ( 1+ \dfrac{0.042}{12})^{47} +Y ( 1+ \dfrac{0.042}{12})^{46} +...+ Y ( 1+ \dfrac{0.042}{12})$

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$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{(1.0035-1)}$

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The above amount is then equal to $5000

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$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035} = 5000$

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3 years ago

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3 years ago

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False​

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False