If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
The two expressions could be :
2 - 1/2m
2 - m / 2
Answer: <em>81</em>
Step-by-step explanation:
<em>3^4</em>
<em>3x3x3x3</em>
<em>3x3=9</em>
<em>9x3=27</em>
<em>27x3=</em><em>81</em>
Answer:
Wait From What I See Aren't You Just Supposed To Put A Name And Date?
Step-by-step explanation:
Answer:
hope this helps!
Step-by-step explanation:
You have to divide:
1.9x10^-8 ÷ (4.2x10^-13)
= appr .45 x 10^5
= .45 x 100000
= appr 45,000 times as large
source: https://www.jiskha.com/questions/1857280/estimate-how-many-times-larger-1-9x10-8-is-than-4-2x10-13
credit: mathhelper
