3 years ago

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False

Mathematics

1 answer:

swat323 years ago

8 0

Answer:

True

Step-by-step explanation:

We can plug in and see.

If (3,0) is on the graph of P, then P(3) will evaluate to 0.

Let's try it:

P(3)=(3)^3-7(3)^2+15(3)-9

P(3)=27-7(9)+45-9

P(3)=27-63+45-9

P(3)=-36+45-9

P(3)=9-9

P(3)=0

Since P(3)=0, then (3,0) is an ordered pair of P.

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The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False​

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False