Hi!
To solve this, we must make an equation in y = mx + b form, where m is the slope and b is the y-intercept.
Since we are looking at a graph with points, it saves us a TON of work, and all we have to do is simply look at the graph. We only need to find m and b, that's it!
M is the slope, and the slope can be represented by the change between points on a line, also known as <em>rise/run. </em>
If we start at point (-4, -1), and go to point (-2, 0), we can see that it goes up 1 and right 2, which would be represented as 1/2.
B is the y-intercept, and that is simply the point that is on the y-axis, which is the point (0, 1), so our number would be 1.
Therefore, plugging these numbers into the equation, our equation is y = <em>1/2</em>x + <em>1</em>
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Hope this helps! :D
1.) 4 - t = 3(t - 1) - 5
4 - t = 3t - 3 - 5
4 - t = 3t - 8
3t + t = 4 + 8
4t = 12
t = 12/4 = 3
2.) 8x - 2(x + 1) = 2(3x - 1)
8x - 2x - 2 = 6x - 2
6x - 2 = 6x - 2
0 = 0
solution is identity.
3.) 3(c - 2) = 2(c - 6)
3c - 6 = 2c - 12
3c - 2c = -12 + 6
c = -6
4.) 0.5(m + 4) = 3(m - 1)
0.5m + 2 = 3m - 3
3m - 0.5m = 2 + 3
2.5m = 5
m = 5/2.5 = 2
m = 2
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
ok so S=soda C=chips and G=gum
Step-by-step explanation:
From the information,
s+3=c
(1/2)c=g
from this P=s+c+g
P=s+(s+3)+((s+3)/2)
P=5/2s+9/2
Us would be the answer to this question
