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pickupchik [31]
3 years ago
15

I need help bad plz.

Mathematics
2 answers:
Svet_ta [14]3 years ago
7 0

Answer:257000

Step-by-step explanation: I’m pretty sure hope this helps

anyanavicka [17]3 years ago
6 0

Answer:

2,57 * 10^5 or 257000

Step-by-step explanation:

(5,14 * 10^9) / (2 * 10^4) =

2,57 * 10^5 =

257000

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Jack bought 3 protein bars for a total of $4.26 which equation could be used to find the cost c on dollars of each protein bar
kramer
Answer: (C)

<u>Solution:</u> 
Jack bought 3 bars for $4.26 thus the cost of each bar can be defined as:

c =  \frac{4.26}{3} ⇒ 3c = 4.26
3 0
3 years ago
Eric gets a 7 percent commission for each electronic item he sells .If he sells 3000 worth of elections ,how much commission doe
Bas_tet [7]

Answer:

$210

Step-by-step explanation:

He makes 7% of that which is:

0.07*3000 = 210

So, he makes $210 in commission.

8 0
4 years ago
Read 2 more answers
BD bisects m m Find m
amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

m\angle ABC = 77.2^\circ

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

m\angle ABD=m\angle CBD

Substituting the algebraic expressions for both angles:

2.5x + 8.6=3.5x - 3.4

Subtracting 8.6 and 3.5x:

2.5x - 3.5x = -8.6 - 3.4

Operating:

-x = -12

x = 12

The two angles are:

m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ

m\angle CBD=3.5x - 3.4 = 38.6^\circ

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

m\angle ABC = 2*38.6^\circ=77.2^\circ

\mathbf{m\angle ABC = 77.2^\circ}

6 0
3 years ago
How do I get the answer??
Lubov Fominskaja [6]

Answer:

4√10

Step-by-step explanation:

Hello!

Let's first simplify the radical.

We can do this by expanding the radical:

We need to pull out a perfect square factor to expand a radical and simplify it. In 45, we have 9 and 5 multiplied, and 9 is a perfect square.

Let's work with √45:

  • √45 can be written as √9 * √5 (using the rule √ab = √a * √b)
  • √9 simplifies to 3, so it is 3√5

Now we can simplify the operation in the parenthesis by combining like terms:

  • 3√5 + √5
  • √5 + √5 + √5 + √5
  • 4√5

Now using the same rule as above, we can multiply the values:

  • √2(4√5)
  • 4√10

Your solution is 4√10

3 0
2 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
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