Drag and drop the words below to correctly complete the statement of the SAS Similarity Theorem.

Which expression is equivalent to 200? O 2 /10 O 10/2 O 10/20 O 100/13

creativ13 [48]

Answer:

10/20

Step-by-step explanation:

10 times 20 is 200 which would give you 10/20

hope I did this right

6 0

2 years ago

Determine whether or not 630 is a triangular number. start with the formula t n = n ( n + 1 ) 2 and then use the quadratic formu

ziro4ka [17]

Triangular sequence = n(n + 1)/2

If 630 is a triangular number, then:

n(n + 1)/2 = 630

Then n should be a positive whole number if 630 is a triangular number.

n(n + 1)/2 = 630

n(n + 1) = 2*630

n(n + 1) = 1260

n² + n = 1260

n² + n - 1260 = 0

By trial an error note that 1260 = 35 * 36

n² + n - 1260 = 0

Replace n with 36n - 35n

n² + 36n - 35n - 1260 = 0

n(n + 36) - 35(n + 36) = 0

(n + 36)(n - 35) = 0

n + 36 = 0 or n - 35 = 0

n = 0 - 36, or n = 0 + 35

n = -36, or 35

n can not be negative.

n = 35 is valid.

Since n is a positive whole number, that means 630 is a triangular number.

So the answer is True.

7 0

3 years ago

Is a function always a relation

ziro4ka [17]

Answer:

No, to be a function a relation must fulfill two requirements: existence and unicity.

Step-by-step explanation:

Existence is a condition that establish that every element of te domain set must be related with some element in the range. Example: if the domain of the function is formed by the elements (1,2,3), and the range is formed by the elements (10,11), the condition is not respected if the element "3" for example, is not linked with 10 or 11 (the two elements of the range set).
Unicity is a condition that establish that each element of the domain of a relation must be related with only one element of the range. Following the previous example, if the element "1" of the domain can be linked to both the elements of the range (10,11), the relation is not a function.

3 0

2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago

Use long division to find a repeated decimal equivalency for the fraction 6/9

Sliva [168]

It gets repetitive really fast. The second verse is the same as the first. The result is ...

$\dfrac{6}{9}=0.\overline{6}$

4 0

2 years ago

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