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krok68 [10]
3 years ago
9

Find the length of UV. v(2,-1) u(1,-9)

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer: \sqrt{65}

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the concept of the distance formula.

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

<u>Solve:</u>

Find the length of UV, where:

  • U (1, -9)
  • V (2, -1)

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance = \sqrt{(1-2)^2+(-9+1)^2}

Distance = \sqrt{(-1)^2+(-8)^2}

Distance = \sqrt{1+64}

Distance = \sqrt{65}

Hope this helps!! :)

Please let me know if you have any questions

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%20%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B7x%20-%203%7D%7B2%7D%20" id="Tex
MAVERICK [17]

Answer:

\sf x =\dfrac{2}{3}

Explanation:

\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}

cross multiply

\sf \rightarrow 2(x+1) = 2(7x-3)

divide both sides by 2

\sf \rightarrow x + 1 = 7x-3

isolate variables

\sf \rightarrow x -7x = -3-1

simplify

\sf \rightarrow -6x = -4

divide both sides by -6

\sf \rightarrow \dfrac{-6x}{-6}  = \dfrac{-4}{-6}

simplify

\sf \rightarrow x =\dfrac{2}{3}

4 0
1 year ago
Read 2 more answers
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

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1 year ago
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Harman [31]

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I need the following to answer

Step-by-step explanation:

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2 years ago
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Sergio039 [100]

Answer:

replace the x with (*answer)

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3 0
2 years ago
A bank is offering 3.5% simple interest on a savings account. If you deposit
arsen [322]

Answer: $525

Step-by-step explanation:

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P = Principal = $7500

R = Rate = 3.5%

T = Time = 2 years

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= $525

5 0
2 years ago
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