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Alenkasestr [34]
4 years ago
15

the mass of the Earth is 5,980,000,000,000,000,000,000,000 kilograms. Write this number in scientific notation

Mathematics
2 answers:
Gnoma [55]4 years ago
8 0
<span>5,980,000,000,000,000,000,000,000 
5.98 * 10^24
Just google mass of the Earth.</span>
IgorLugansk [536]4 years ago
7 0
5.8x10^24 would be the answer!
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Tell whether the angles are complementary or supplementary. Then find the value of $x$ . A ray intersects two other rays forming
Mariulka [41]

Answer:

The angles are complementary

x is 55 degrees

Step-by-step explanation:

Complementary angles are angles that sums up to 90 degrees

Since a ray intersects two other rays forming a right angle, hence the sum of the two angles is 90degrees and this shows that the angles are complementary.

Given the two angles to be x and (x-20). Taking their sum and equating it to 90 degrees, we will have;

x + x - 20  = 90

2x - 20 = 90

2x = 90+20

2x = 110

x = 110/2

x = 55 degrees

Hence the value of x is 55degrees

8 0
3 years ago
write the equation of the line that passes through the vertex of the parabola y=-2x^2+12x-11 and the point (-2,47)
pshichka [43]

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\bf \stackrel{vertex}{(\stackrel{x_1}{3}~,~\stackrel{y_1}{7})}\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{47}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{47}-\stackrel{y1}{7}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{3}}}\implies \cfrac{40}{-5}\implies -8

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-8}(x-\stackrel{x_1}{3}) \\\\\\ y-7=-8x+24\implies y=-8x+31

5 0
4 years ago
A sample chosen by stratified random sampling involves a. randomly selecting one of the first k elements in an ordered populatio
Pavlova-9 [17]

Answer:

The answer is (d)= Selecting a simple random sample from each of a given number of strata formed from the elements in the population.

Stratified random sampling is a sampling method where the population has a number of distinct categories. The population can be organized into separate strata and each stratum is then sampled as an independent sub-population out of which individual elements can be randomly selected. In this case, each unit in a stratum, that is, each element in a group has the chance of being selected into the sample and there is adequate representation of minority sub-groups. With Stratified sampling, the best result occurs when elements within strata are internally homogeneous.

Step-by-step explanation:

5 0
3 years ago
Mr. Shipley is in charge of a school trip. 317 students will go on the trip. Thhe school had seven buses and one van. If the van
sergey [27]

Answer:

<u>44 </u>students will ride on each bus.

Step-by-step explanation:

Given:

Mr. Shipley is in charge of a school trip.

317 students will go on the trip.

The school had seven buses and one van.

If the van can haul nine students.

Now, to find the number of students who will ride on each bus.

Total students who will go on trip = 317.

So, we deduct the nine students of van from total students.

317-9=308.

Thus, there are 308 students remaining for riding on the seven buses.

Now, to get the number of students that will be riding on each bus we divide 308 remaining students by number of buses:

308\div 7

=44.

Therefore, 44 students will ride on each bus.

6 0
3 years ago
Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.
MAXImum [283]

Using the t-distribution, the 96% confidence interval is given as follows:

(18.96, 21.04).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

\overline{x} = 20, s = 5, n = 100

Hence the bounds of the interval are:

\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96

\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

6 0
2 years ago
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