which of the following is the quotient of the rational expressions shown below 2x/4x+3 divided x-1/2x

What is 700÷80 and with the remainder thanks

Viefleur [7K]

Answer:

640 R = 60

Explain Your Answer:

7 0

3 years ago

Please help me answer these 2 questions, worth lots of points

alexgriva [62]

For the first one, to find x, you are going to take that entire side which would equal to 180 and solve. 2x+20+55=180 would then go down to 2x+65=180 once you add the 20 and 55. Then subtract 65 to both sides and divide your final answer 115/2 which is x=57.5. For the second one it’s 4x-2+21=180, then you will subtract 2 from 21 and get 19. After you would subtract 19 by 180 and divide 4 by each side, getting x=40.25 as your final answer.

7 0

3 years ago

A vitamin C tablet contains 1/40 of a gram of vitamin C. You take 1 1/2 tablets every day. How many grams of vitamin C do you ta

enyata [817]

1/40*1.5=3/80=0.0375

8 0

3 years ago

PLEASE HELP MEEE !!!!

WINSTONCH [101]

Answer:

Step-by-step explanation:

Lets find out first the Area of the rectangle building

A=50*100=5000 ft^2

we have 2 circles with the radius of 42 ft, r=21ft

Acircle=3.14*(21)^2=1384.74

Area of 2 circles=2*1384.74=2769.48

What is not covered by the rings is

5,000.00-2769.48=2230.52, rounded is 2231

Choice A

5 0

3 years ago

Read 2 more answers

The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from

Vinvika [58]

Answer:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

$df=n_1 +n_2 -2=13+19-2=30$

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

$\bar X_{1}=810$ represent the mean for sample 1

$\bar X_{2}=770$ represent the mean for sample 2

$s_{1}=67$ represent the sample standard deviation for 1

$s_{2}=56$ represent the sample standard deviation for 2

$n_{1}=13$ sample size for the group 2

$n_{2}=19$ sample size for the group 2

$\alpha=0.05$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=13+19-2=30$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

4 0

3 years ago