False
foci of an ellipse cannot be outside the ellipse
2x + 3y = 26 -- equation 1
3x + 5y =40 -- equation 2
(Equation 1) * 3
6x + 9y = 78 -- equation 3
(Equation 2) * 2
6x + 10y = 80 -- equation 4
(Equation 4) - (Equation 3)
y = 2 -- equation 5
(Equation 5)'s value of y into (Equation 1)
2x + 3(2) = 26
2x = 20
x = 10
Thus x = 10 and y = 2
Hope that helps!
Answer:
Yes, this graph represents a function.
Functions can have a maximum of one y-value for every x-value. On a graph, this means it passes the vertical line test.
Step-by-step explanation:
The vertical line test is when a vertical line is passed though the graph. If at any point the vertical line touch more than one point on the graph, the graph is not a function. Vertical line test is also known as VLT.
First set up an equation in n:-
3n + 10 = 8n
add -3n to both sides;-
10 = 5n
Yes, because the afternoon rate is just the morning rate split in half. Instead of checking the temperature every hour and a half, the temperature was checked every 45 minutes. And, the temperature rate was also split in half when the time was split in half. So basically, if the 2 degrees every 45 minutes was multiplied by 2,(both the time and the temperature) or if the 4 degrees every 90 minutes was divided by 2, (once again, both the time and the temperature) then, they would both be either 2 degrees every 45 minutes, or they would both be 4 degrees every 90 minutes.
