One has said that it is 5%. though, that statement is not correct. an impossible event means there is a zero probability that the event starts. impossible in video games is just difficult for even the most skilled players, so the one who said it was 5%, he/she was way into video games at the time. so, it will most likely be zero obviously.
thanks for asking the question. i will be there anytime.
The answer would be A. <3 hope this helps!
THE ANSWER IS THE LAST ONE
Answer:
By putting x = -x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.
Step-by-step explanation:
We need to explain why the function of
is neither even or odd
First we will understand, when the function is even and odd
Even function:
<em>A function is even if f(-x) = f(x) </em>
Odd function:
<em>A function is odd if f(-x) = -f(x) </em>
So, if we get the above result by putting x = -x, then we can say that the function is even or odd.
If we don't get any of the above results then the function is neither even nor odd.
So, for the given function: ![f(x)=4x^2+8x](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E2%2B8x)
Put x = -x
![f(x)=4x^2+8x\\Put x=-x\\f(-x)=4(-x)^2+8(-x)\\f(-x)=4x^2-8x](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E2%2B8x%5C%5CPut%20x%3D-x%5C%5Cf%28-x%29%3D4%28-x%29%5E2%2B8%28-x%29%5C%5Cf%28-x%29%3D4x%5E2-8x)
So, by putting x=-x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.
Answer:
Option B. y = csc(x) + 1
Step-by-step explanation:
If we have to draw an asymptote graph( csc graph), we should draw the graph of sine first.
For y = a sin(bx+c) +d
Here from the given graph
a = (0+2)/2 = 1
period = (3π/2-π/2) = 2π
Therefore b = 2π/period = 2π/2π = 1
b = 1
Vertical shift d = 1
Now the equation will be y = 1×sin(1.x+0)+1
y = sinx + 1
Now we draw the sine graph y = sinx +1
Then we draw asymptotes touching the maximum and minimum values of sine graph.
Which reflects It's a graph of y = csc(x) + 1
Therefore option B. is the right answer.