<h2>
<em>Answer:</em></h2><h2>
<em>Yes</em></h2>
<em>Just </em><em>divide </em><em>1</em><em>6</em><em> </em><em>and </em><em>2</em><em>4</em><em> </em><em>by </em><em>8</em><em>,</em><em> </em><em>you </em><em>will </em><em>get </em><em>2</em><em>/</em><em>3</em><em> </em><em>as </em><em>a </em><em>result.</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
The answer is D to the next step
B- the volume of a cone is pi(r^2)(h/3) where r=radius and h= height.
When you plug in r &h you get pi(6^2)(19.6/3) =
pi(36)(6.53)=738.9
As far as I can make out this one.
the bunker is a 3D object, it has a height, with and length, however we're only concerned with the 2D front face, which has a length and width only.
we know the x-axis is the ground level, so the y-axis must be the scale for the length.
if we can find, using the provided model, the x-intercepts, namely where the x-axis gets touched, we can just get the distance between them and that's the ground level width.
keeping in mind that when the graph touches the x-axis, an x-intercept, "y" is 0.

now, the distance from (-72, 0) and (72, 0) is just 72 +72, or 144.
the measurement for 18.9 m is 0.05