If one-sixth of a certain number is four more than one-twelfth the number, the required number will be 48.
Let the unknown number be 'a'
One-sixth of the number is expressed as 1/6 a ..... 1
One-twelfth the number is also expressed as 1/12 a
Four more than one-twelfth the number will be written as:
1/12 a + 4 .... 2
Equating 1 and 2 will give:
1/6 a = 1/12 a + 4
a/6 = a/12 + 4
Collect the like terms
![\frac{a}{6} - \frac{a}{12} = 4](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7B6%7D%20%20-%20%5Cfrac%7Ba%7D%7B12%7D%20%3D%204)
Find the LCM
![\frac{2a-a}{12} = 4\\\frac{a}{12} = 4](https://tex.z-dn.net/?f=%5Cfrac%7B2a-a%7D%7B12%7D%20%3D%204%5C%5C%5Cfrac%7Ba%7D%7B12%7D%20%3D%204)
Cross multiply
a = 12×4
a = 48
This shows that the required number is 48
Learn more on equations here: brainly.com/question/14034270
Hope this helps. If you have any further question ask in comments.
Answer:
-5
Step-by-step explanation:
Remember the slope intercept form:
y = mx + b
m = Slope value
b = y-intercept
So in this case,
y = (-5)x + b
m = -5
b = 1
Thus the answer is -5
Answer:
Step-by-step explanation:
Given question is incomplete: Find the compete question in the attachment.
a). Skew lines neither the parallel lines nor they intersect each other.
Two pairs of skew lines are BF and EH, & CG and EF.
b). Since EFGH and ABCD are rectangular planes and BF and DH are perpendicular to them,so both will be the altitudes between the planes.
Therefore, BF and DH will pe parallel.
c). BD and DH are the diagonals of the planes parallel to each other.
Therefore, BD and DH will be parallel.
d). Since BD and plane EFG don't intersect each other, so the solution will be an empty set.
e). HG is perpendicular to DH. So,the planes BDH and FHG containing these lines will be perpendicular to each other.
Ok from the given the best choice to go with will be option B because its going from an up right and its going to flip and rotate.